A simply supported beam has a section given in (a), with normal-weight concrete compressive strength f.' = 4500 psi, flexural reinforcement strength f, = 60,000 psi, and shear reinforcement strength fy= 40,000 psi. The load in given as shown in (b). 34 in. D - 1.3 kips/t L = 1.6 kips/ft 6 in. { = 30 t 14 in. d = 24 in.

A simply supported beam has a section given in (a), with normal-weight concrete compressive strength f.' = 4500 psi, flexural reinforcement strength f, = 60,000 psi, and shear reinforcement strength fy= 40,000 psi. The load in given as shown in (b). 34 in. D - 1.3 kips/t L = 1.6 kips/ft 6 in. { = 30 t 14 in. d = 24 in.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A reinforced concrete T-beam contains 1.25x10 m² of steel reinforcement on the tension side. If the steel stress is limited to 115 MN/m² and the concrete stress to 6.5 MN/m², estimate the permissible bending moment. The modular ratio is 15. 30 cm- 12 (0.30-m -60 cm- 10cm -000-1.25 x 10³m² 15cm
Example AT beam R.C. floor system consists of 120 mm thick slab supported by beams at 3 m centre to centre. The effective width and depth of web is 300 mm x 580 mm as shown in Fig. 3.13. Main reinforcement consists of 8 bars of 20 mm diameter. The grade of concrete and steel used are M20 and Fe 415 respectively. Determine the moment of resistance of the T beam, if it is used as simply supported beam of span 3.6 m. by 1620 mm. 300 mm 580 mm 120 mm X
Do not use chatgpt and pls don't provide image solution otherwise I will downvote you
Q1) The cantilever beam is subjected to axial load as shown Below, determine the actual stresses acting at points A, B, C and D. 10 kN 50 100 man 20 kN 15 KN
Q1] A simply supported rectangular beam of 5m span carries characteristic pearmeant action(Excluding self weight of beam) of 10KN/m and variable action of 6KN/m respectively. The beam dimensions are breadth=250mm, effective depth=400mm. Assuming the following material strengths, Design the reinforcement . Fck=35N/mm², Fyk=500N/mm?.
Referenced concrete Number of student 1
A plywood beam is built up of 6-mm strips separated by blocks as shown in Fig. P-577. What shearing force V will cause a maximum shearing stress of 1.4 MPa?
I need help on this question: a) Find strain energy for truss AC. The answer should be in J to 2 decimal places. (positive value indicates tension, negative value compression) b) Find strain energy for truss AB. The answer should be in J to 2 decimal places. (positive value indicates tension, negative value compression) c) Find Strain energy for truss BC. The answer should be in J to 2 decimal places. (positive value indicates tension, negative value compression)
I need correct solution
( CECE2240 - Design of structure -1 ) EXPERIMENT :Designing and detailing of singly reinforced simply supported beam - ACI Code Step 1 Step 2 Step 3 Step 4
Design Problem 5 Determine the spacing of 10 mm U Stirrups required for the beam of design problem 4.0 at Ls = 1.10 m from the support if fpu is 1,724 MPa for the prestressing steel and fy for the stirrups is 276 MPa. Aps = 945.16 mm² (Use NSCP Equation, Table 409.6.3.3e)
A concrete floor slab measuring 6 m x 3 m is simply supported on one side brick load bearing walls along the 6 m sides. The concrete slab is 200 mm thick and reinforced at the bottom as follows.1. Main reinforcement (short span i.e the bars are parallel to the short span), Y 12, shape code 34 @ 125 mm centre to centre,2. Distribution reinforcement (long span i.e the bars are parallel to the long span), Y 10, shape code 20 @ 300 mm centre to centre,3. Concrete cover, 30mm,4. Concrete strength, 40MPa.Draw the reinforcement layout for this slab, in plan and section, indicating all the reinforcement and necessary information required by the contractor. You must calculate and indicate the number of bars required on your drawing. You do not need to calculate the bar lengths and the curtailment. Your drawing must be neat.