A simple random sample of size n = = 200 individuals who are currently employed is asked if they work at home at leastonce per week. Of the 200 employed individuals surveyed, 26 responded that they did work at home at least once perweek. Construct a 99% confidence interval for the population proportion of employed individuals who work at home atleast once per week.The lower bound isThe upper bound is-CBOD(Round to three decimal places as needed.)(Round to three decimal places as needed.)TanD

We have given that, Favourable cases (x) = 26 and sample size (n) = 200Then,We will find 99%…

Answered: A simple random sample of size n = 200…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a. interpret the corresponding 95% confidence intervals for both Birth weight and Age. b. What is the predicted average SBP of an infant born with birth weight 8lbs (128oz) measured at 3 days old? c. Calculate the Pearson correlation between Age and Birth weight, and test if this correlation is significant at the 0.05 level. Does this answer surprise you, why or why not?
Answer A B C
QUESTION 23 Ali constructed a 98% confidence interval for the mean amount spent per day in a shopping mall based on 100 customers. The confidence interval was found to be (AED 1150, AED 2150). Select all correct answers. The mean amount spent per day by the 100 customers selected in the sample falls between AED 1150 and AED 2150. We are 98% confident that the mean amount spent per day by customers falls between AED 1150 and AED 2150. The mean amount spent per day by all customers falls between AED 1150 and AED 2150. 98% of all customers spent between AED 1150 and AED 2150 per day.
For the data set below, calculate r, r2, and a 95 percent confidence interval in r units. Then write a one- to two sentence conclusion statement that includes whether the null hypothesis was rejected or not and whether there is a strong /weak/no relationship. Assume a two tailed hypothesis and α = .05. Case 1 Case 2 Case 3 Case 4 Case 5 Case 6 X 1.05 1.15 1.30 2.00 1.75 1.00 Y 2 2 3 4 5 2
Find the following. Enter your answer rounded to at least two decimals. z a/2 for the 97% confidence interval
A certified mechanic was timed for the repair of an automobile on 14 separate occasions.Over the same period a trainee mechanic was timed for the repair of a similar automobile.The times in minutes are given belowCertified 344 276 257 334 267 164 222 343 212 175 211 311 209 188Trainee 222 342 178 234 398 232 377 211 309 190 351 343 177 269 a. Calculate a 99% confidence interval for the mean time taken to repair the automobileby the (i) certified mechanic and (ii) the trainee mechanic. b. Test the hypothesis that the two mean times for both mechanics are equal. Use the 5%level of significance. Subsequently, it was learnt that the times for the trainee were incorrecly recorded andthat each of the values above is 30 minutes too small. What, if any, difference doesthis make to the results of the test done in part (b)?
The following data represent a random sample of five measurements from a normally distributed population: 7,4,2,5,7 a. Find 90% confidence interval for u. b. Find a 99% confidence interval for u.
Next question If a sample proportion is 0.68, which of the following could be a 90% confidence interval for the population proportion? ..... Select all that apply. A. Lower bound: 0.59; Upper bound: 0.77 B. Lower bound: 0.66; Upper bound: 0.70 OC. Lower bound: 0.50; Upper bound: 0.77 D. Lower bound: 0.77; Upper bound: 0.95 E. Lower bound: 0.67; Upper bound: 0.71 F3 F4 F5 F7 F8 24 4. %23 2 3. 6. Left control option command
Verizon Wireless would like to estimate the proportion of households that use cell phones for their phone service without a land line. A random sample of 150 households was selected and 48 relied strictly on cell phones for their service. The 95% confidence interval for the proportion based on this sample is ________. A) (0.257, 0.383) B) (0.223, 0.417) C) (0.185, 0.456) D) (0.165, 0.475)
The following numbers represent five randomly selected individuals’ ages: 20, 32, 36, 42, 45. If the age distribution for the whole population follows a normal distribution, which one represents the 90% confidence interval for the mean age based on this particular sample? A ) (20.26, 49.74) B ) (25.66, 44.34) C ) (14.83, 55.17) D ) (28.28, 41.72) E ) (23.72, 46.28)
Help with question 3 and 4
A random sample of 21 lunch orders at Noodles & Company showed a mean bill of $13.54 with a standard deviation of $6.45. Find the 98 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) The 98% confidence interval is from ___to___

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