A simple particle accelerator is built using a large parallel plate capacitor (two plates of metal at different voltages separated by some distance) sending a charged particle between them towards a whole in one plate. A diagram of this is below. If the two plates are given a potential V₁ = OV and V = 120V what would the exiting speed of an electron be if it started out stationary at the Vį plate? Vi Vf
A simple particle accelerator is built using a large parallel plate capacitor (two plates of metal at different voltages separated by some distance) sending a charged particle between them towards a whole in one plate. A diagram of this is below. If the two plates are given a potential V₁ = OV and V = 120V what would the exiting speed of an electron be if it started out stationary at the Vį plate? Vi Vf
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Transcribed Image Text:## Question: Particle Acceleration in a Parallel Plate Capacitor
A simple particle accelerator is built using a large parallel plate capacitor (two plates of metal at different voltages separated by some distance) sending a charged particle between them towards a hole in one plate. A diagram of this is below.
If the two plates are given a potential \(V_i = 0V\) and \(V_f = 120V\), what would the exiting speed of an electron be if it started out stationary at the \(V_i\) plate?
### Diagram Explanation:
- The diagram shows two parallel plates.
- The left plate is labeled \(V_i\) with a voltage of \(0V\).
- The right plate is labeled \(V_f\) with a voltage of \(120V\).
- An electron starts stationary at the \(V_i\) plate and is accelerated across the space between the plates.
- The movement direction is indicated by an arrow pointing from the left to the right plate, ending at a small gap or hole in the \(V_f\) plate.
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