A simple elevator ride can teach you quite a bit about the normal force. There are three different scenarios given detailing the rider's experience in an unnamed hotel. For each scenario, calculate the normal force FN,1-3 acting on the rider if his mass is m = 78.1 kg and the acceleration due to gravity g = 9.81 m/s² .

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A simple elevator ride can teach you quite a bit about the normal force. There are three different scenarios given detailing the rider's experience in an unnamed hotel. For each scenario, calculate the normal force \( F_{N,1-3} \) acting on the rider if his mass is \( m = 78.1 \, \text{kg} \) and the acceleration due to gravity \( g = 9.81 \, \text{m/s}^2 \).

**Scenario 1:** The elevator has constant velocity.

- The illustration shows a man standing in an elevator that is moving with a constant velocity, indicating no acceleration. 
- Formula: \( F_{N,1} = \) [Box for answer] N

**Scenario 2:** The elevator is moving with upward acceleration \( a_2 = 5.51 \, \text{m/s}^2 \).

- In this scenario, the elevator is shown moving upward, with an arrow indicating the positive acceleration direction.
- Formula: \( F_{N,2} = \) [Box for answer] N

**Scenario 3:** The cable breaks, and the elevator accelerates downward at \( a_3 = g = 9.81 \, \text{m/s}^2 \).

- The diagram represents the elevator in free fall with the acceleration equal to gravity.
- Formula: \( F_{N,3} = \) [Box for answer] N

In these scenarios, students are expected to apply their understanding of physics to calculate the normal force in each situation based on the elevator's motion and the rider's mass.
Transcribed Image Text:A simple elevator ride can teach you quite a bit about the normal force. There are three different scenarios given detailing the rider's experience in an unnamed hotel. For each scenario, calculate the normal force \( F_{N,1-3} \) acting on the rider if his mass is \( m = 78.1 \, \text{kg} \) and the acceleration due to gravity \( g = 9.81 \, \text{m/s}^2 \). **Scenario 1:** The elevator has constant velocity. - The illustration shows a man standing in an elevator that is moving with a constant velocity, indicating no acceleration. - Formula: \( F_{N,1} = \) [Box for answer] N **Scenario 2:** The elevator is moving with upward acceleration \( a_2 = 5.51 \, \text{m/s}^2 \). - In this scenario, the elevator is shown moving upward, with an arrow indicating the positive acceleration direction. - Formula: \( F_{N,2} = \) [Box for answer] N **Scenario 3:** The cable breaks, and the elevator accelerates downward at \( a_3 = g = 9.81 \, \text{m/s}^2 \). - The diagram represents the elevator in free fall with the acceleration equal to gravity. - Formula: \( F_{N,3} = \) [Box for answer] N In these scenarios, students are expected to apply their understanding of physics to calculate the normal force in each situation based on the elevator's motion and the rider's mass.
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