A simple curve having a radius of 229.18 m has a back tangent of N 28° E, and a forward tangent of N 66° E. A property line running parallel to the back tangent crosses the centerline of the curve at a distance of 10 m from it. The PC of the curve is located at 10+120.60. a) What is the deflection angle at the point of intersection of the property line and the curve measured from the tangent at station 10+120.60? b) What is the stationing at the point of intersection of the property line and the curve? c) Compute the chord distance from PC to the point of intersection of the property line and the Cunve?

A simple curve having a radius of 229.18 m has a back tangent of N 28° E, and a forward tangent of N 66° E. A property line running parallel to the back tangent crosses the centerline of the curve at a distance of 10 m from it. The PC of the curve is located at 10+120.60. a) What is the deflection angle at the point of intersection of the property line and the curve measured from the tangent at station 10+120.60? b) What is the stationing at the point of intersection of the property line and the curve? c) Compute the chord distance from PC to the point of intersection of the property line and the Cunve?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The azimuth of the tangents of the simple curve is 490 degrees and 764 degrees respectively. The radius of the curve is 211.2 meters. Station A is lying on the curve having a deflection angle of 9 degrees from PT. Determine the length of chord from PC to PT in meters.
Four tangents having an angle of intersections shown is to be connected by three simple curves having different radius with the last curve which is the 5 times sharper than the first curve. Find the radius of the each curve. AB = 300 m, BC = 200 m.
A horizontal curve with a deflection angle of 60o30' and degree of curvature of 5o as shown in Figure 5 is to be set out at whole station intervals of 100ft. If the point of curvature (PC) is located at a station 121+25.66, determine.i. the length of the curve and the station of PTii. the deflection angles VAp, VAq, VAv and Vas
3. The tangents of a simple curve have bearings of N 20 degrees E and N 80 degrees E respectively. The radius of the curve is 200 m. a. Compute the stationing of point A on the curve having a deflection angle of 6 degrees from the P.C which is at 1+200.00.
Q1B) A circular horizontal curve having radius (R)=100 m and Deflection angle (0)= 60°. Compute the basic elements (L,LC,T,M,E) of the curve. gure below:
the deflection angles of two intermediate points x and y on a simple curve measured from the tangent passing through pc are 6.97° and 12.8°, respectively. the distance along the curve between x and y is 34.72 m. compute the for the degree of curve in degrees. use arc basis.
QUESTION 1 The long chord from the PC to the PT of a compound curve is 300 m. A common tangent, from point A to B, has an angle of 12° with AV and 15⁰ with BV. If the common tangent is parallel to the long chord, determine: a. the radius of the first curve Answer: R₁= b. the radius of the second curve Answer: R₂= c. the stationing of PT if PC is 10+204.30 Answer: Sta PT= m m Note: Unit has been provided after the blank space. No need to indicate units on your answer.
Show your COMPLETE solution in 3 decimal places. Provide illustration and label accordingly. 4.A simple curve having a radius of 229.18m has a back tangent of N28 ̊E and a forward tangent of N66 ̊E. A property line runningparallel to the back tangent crosses the curve at a distance of 10m from it. If the PC of thecurve is at 10+120.6. (a) What is the deflection angle at the point of intersection of the property line and the curve measured from the tangent at station 10+120.6, (b) What is the stationing at the point of intersection of the property line and the curve, and (c) Compute the chord distance from the PC to the point of intersection of the property line and the curve?
The azimuth of the tangents of the simple curve is 480° and 740° respectively. The radius of the curve is 180m. Station A is lying on the curve having a deflection angle of 8° from PT. Determine the length of curve from PT to Point A in meters.
A simple curve which has a two points A and B with a deflection angle of 4ᴏ and 6ᴏ . The chord distance between the two points is 20m and the angle of intersection it made is 24ᴏ . Find the radius of the curve, the chord distance between PC and point A and the tangent distance of the said simple curve.
Additional question:1. The value of intersection Angle of the Second curve is 23.66 deg (103.7553 - 84.0945). What is the length of curve 2? 2. What is the value of the intersection angle of the first curve? 3. What is the curve length of the first curve?
The length of the curve of a simple curve having a degree of curve 4o is equal to 210 m. Compute the area of the fillet of the curve. Choices: 1442.69 m2 1244.69 m2 1224.69 m2 1424.69 m2