A simple curve has a central angle of 36° and a degree of curve of 6°. Find the nearest distance from the mid point of the curve to the point of intersection of the tangents. Find the distance from the mid point of the curve to the mid points of the long chord joining the point of curvature and point of tangency. If the stationing of the point of curvature is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8° with the tangent through the P.C.
A simple curve has a central angle of 36° and a degree of curve of 6°.
-
Find the nearest distance from the mid point of the curve to the point of intersection of the tangents.
-
Find the distance from the mid point of the curve to the mid points of the long chord joining the point of curvature and point of tangency.
-
If the stationing of the point of curvature is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 8° with the tangent through the P.C.
A simple curve connects two tangents AB and BC with bearings N 85°30’ E and S 68°30’ E, respectively. If the stationing of the vertex is 4 + 360.2 and the stationing of PC is 4 + 288.4
-
Determine the radius of the simple curve.
-
Determine the long chord distance.
-
Determine the stationing of PT.
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 1 images
