a) Sieve analysis of sand sample gave the following results: Mass retained (gm) Sieve No. 6-8 73 8-10 11 29 159 10-12 12-18 18-20 161 20-30 300 219 30-40 40-50 50-70 121 143 The sample is sieved so as to remove all the sand larger than sieve No.8 and all the sand finer than sieve No. 50 i. Determine if the remaining sand is suitable for use in rapid sand filters

a) Sieve analysis of sand sample gave the following results: Mass retained (gm) Sieve No. 6-8 73 8-10 11 29 159 10-12 12-18 18-20 161 20-30 300 219 30-40 40-50 50-70 121 143 The sample is sieved so as to remove all the sand larger than sieve No.8 and all the sand finer than sieve No. 50 i. Determine if the remaining sand is suitable for use in rapid sand filters

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter2: Origin Of Soil And Grain Size

Section: Chapter Questions

Problem 2.1CTP: Three groups of students from the Geotechnical Engineering class collected soil-aggregate samples...

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In a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: O There is no clay in the sample ) the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample O 95.5% of the sample is Sand and Silt O O
If the weight of sample of sand in sieve analysis test was 420 gm and the weight retained on sieve are shown in table below. Is the sand satisfying the specification? Calculate the fineness modulus of sand and what is the average size ? Sieve size 10 2.36 1.18 0.6 0.3 0.15 < 0.15 (mm) Weight 8.4 63 96.6 143 59 34 16 retained (gm) Sieve size Specification limits for cumulative passing (mm) Zone 1 Zone 2 Zone 3 Zone 4 9.5 100 100 100 100 4.75 100 - 90 100 - 90 100 - 90 100 -95 2.36 95 -60 100 - 75 100 - 85 100 - 95 1.18 70 - 30 90 - 55 100 - 75 100 - 90 0.6 34 15 59 - 35 79 - 60 100 - 80 0.3 20 - 5 30 - 8 40 - 12 50 - 15 0.15 10 - 0 10 - 0 10 - 0 15 - 0 < 0.15 ------ ------
mpt=541762&cmid%3D103601 Marks 25 Question 1 A sample of AL Batina soil tested in the laboratory. The gradation analysis results are as shown in table Q1. The Atterberg limit tests indicate that the liquid limit is LL = 30% and the plastic limit is PL=27%. Table Q1 Sieve No.# Sieve size (mm) Finer (%) 4 4.75 90 8. 2.36 84 16 1.3 60 30 0.6 30 50 0.2 10 200 0.075 8 i. Determine the uniformity coefficient Marks] ii. Determine curvature coefficient [5 [5 Marks] iii. Classify AL Batina soil according to Unified Soil Classification System (USCS). [10 Marks] iv. Determine the group symbol and group name Marks) [5
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A 627-g sample of sand was found to have the following amounts of material retained on each sieve/pan: 3/8 in. = 22 g, No. 4 = 45 g, No. 8 = 96 g, No. 16 = 122 g, No. 30 = 163 g. No. 50 86 g, No. 100 = 51 g, No. 200 = 30 g, pan = 11 g a. Calculate the fineness modulus of the sand. b. Is this sieve analysis valid for acceptance purposes? Explain why. c. Does the sand meet the particle size criteria of ASTM C 33. Fully justify your answer (list and check all relevant criteria from ASTM C33)
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The sand obtained from a river are generally not suitable formediumfilter application due to its ineffective sizes. Therefore, the modification of this stock sand needs to be done in order to produce the desired filter sand. The sieve analysis of this stock sand was carried out and the results should be shown in your answers. Propose the sizes that should be eliminated during the modification process for a purpose of developing usable filter sand with an effective size and uniformity coefficient of 0.45 mm and 1.6, respectively.
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Express the answers in the nearest three decimal numbers. NOTE: Refer to MM = 08 and DD = 26
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