(a) Show that if A has the repeated eigenvalue 1 with two linearly independent associated eigenvectors, then every nonzero vector v is an eigenvector of A. (Hint: Express v as a linear combination of the linearly independent eigen- vectors and multiply both sides by A.) (b) Conclude that A must be given by Eq. (22). (Suggestion: In the equation Av = Av take v = [1 0]' and v = [0 1]'.)

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.1: Inner Product Spaces
Problem 11AEXP
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Here A represents a 2 x 2 matrix

(a) Show that if A has the repeated eigenvalue 1 with two
linearly independent associated eigenvectors, then every
nonzero vector v is an eigenvector of A. (Hint: Express v
as a linear combination of the linearly independent eigen-
vectors and multiply both sides by A.) (b) Conclude that
A must be given by Eq. (22). (Suggestion: In the equation
Av = Av take v = [1 0]' and v = [0 1]'.)
Transcribed Image Text:(a) Show that if A has the repeated eigenvalue 1 with two linearly independent associated eigenvectors, then every nonzero vector v is an eigenvector of A. (Hint: Express v as a linear combination of the linearly independent eigen- vectors and multiply both sides by A.) (b) Conclude that A must be given by Eq. (22). (Suggestion: In the equation Av = Av take v = [1 0]' and v = [0 1]'.)
Expert Solution
Step 1

Given : A is a 2×2 matrix and A has the repeated eigen value λ with two linearly independent eigen vectors.

To prove : Every non zero eigen vector v is an eigen vector of A.

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