A set of data items is normally distributed with a mean of 60. Convert the data item to a z-score, if the standard deviation is as given. data item: 96; standard deviation: 9 OA. 000 55/3 B. 36 C. 4 D. 9 ***

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Question:**

A set of data items is normally distributed with a mean of 60. Convert the data item to a z-score, if the standard deviation is as given.

- Data item: 96
- Standard deviation: 9

**Options:**

- A. \(\frac{5}{3}\)
- B. 36
- C. 4
- D. 9

**Explanation:**

To convert the data item to a z-score, use the formula:

\[ z = \frac{(X - \mu)}{\sigma} \]

Where:
- \( X \) is the data item (96)
- \( \mu \) is the mean (60)
- \( \sigma \) is the standard deviation (9)

Substitute the values into the formula to find the z-score.
Transcribed Image Text:**Question:** A set of data items is normally distributed with a mean of 60. Convert the data item to a z-score, if the standard deviation is as given. - Data item: 96 - Standard deviation: 9 **Options:** - A. \(\frac{5}{3}\) - B. 36 - C. 4 - D. 9 **Explanation:** To convert the data item to a z-score, use the formula: \[ z = \frac{(X - \mu)}{\sigma} \] Where: - \( X \) is the data item (96) - \( \mu \) is the mean (60) - \( \sigma \) is the standard deviation (9) Substitute the values into the formula to find the z-score.
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