A series of bricks, whose thickness are all equal to 1.3 m, are arrange according to the figure shown below 0.53 m 0.53 m A E O F B 1m C G D 1m H Thermal Conductivities 1m Material A BUDE D F G H Convective Coefficient hi 12 kW/m2-K ho 23 kW/m2-K The left side is exposed to 33 C air temperature while the right side is exposed to air at a temperature of 12 C. Assume unidirectional and steady state flow along x-direction. Neglect radiation effects K (kW/m-K) 0.50 1.3 0.50 0.75 0.75 0.5 1.3 0.3 Calculate the total heat flow, and overall heat transfer coefficient of the system. Also calculate the temperature between the interface of A and BC, E and F, G and H.
A series of bricks, whose thickness are all equal to 1.3 m, are arrange according to the figure shown below 0.53 m 0.53 m A E O F B 1m C G D 1m H Thermal Conductivities 1m Material A BUDE D F G H Convective Coefficient hi 12 kW/m2-K ho 23 kW/m2-K The left side is exposed to 33 C air temperature while the right side is exposed to air at a temperature of 12 C. Assume unidirectional and steady state flow along x-direction. Neglect radiation effects K (kW/m-K) 0.50 1.3 0.50 0.75 0.75 0.5 1.3 0.3 Calculate the total heat flow, and overall heat transfer coefficient of the system. Also calculate the temperature between the interface of A and BC, E and F, G and H.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![A series of bricks, whose thickness are all equal to 1.3 m, are arrange according to the figure
shown below
0.53 m
0.53 m
A
E
-O
F
B
1m
C
G
D
1m
H
Thermal Conductivities
1 m
Material
A
B
с
D
E
Convective Coefficient
hi 12 kW/m2-K
ho=23 kW/m2-K
The left side is exposed to 33 C air temperature while the right side is exposed to air at a
temperature of 12 C. Assume unidirectional and steady state flow along x-direction. Neglect
radiation effects
F
G
H
K (kW/m-K)
0.50
1.3
0.50
0.75
0.75
0.5
1.3
0.3
Calculate the total heat flow, and overall heat transfer coefficient of the system.
Also calculate the temperature between the interface of A and BC, E and F, G and H.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b13c60b-8d18-4823-b8e9-108515c0302b%2F31805073-2112-451f-90ae-63c18285f99d%2Fhwyfy5e_processed.png&w=3840&q=75)
Transcribed Image Text:A series of bricks, whose thickness are all equal to 1.3 m, are arrange according to the figure
shown below
0.53 m
0.53 m
A
E
-O
F
B
1m
C
G
D
1m
H
Thermal Conductivities
1 m
Material
A
B
с
D
E
Convective Coefficient
hi 12 kW/m2-K
ho=23 kW/m2-K
The left side is exposed to 33 C air temperature while the right side is exposed to air at a
temperature of 12 C. Assume unidirectional and steady state flow along x-direction. Neglect
radiation effects
F
G
H
K (kW/m-K)
0.50
1.3
0.50
0.75
0.75
0.5
1.3
0.3
Calculate the total heat flow, and overall heat transfer coefficient of the system.
Also calculate the temperature between the interface of A and BC, E and F, G and H.
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Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
Which is correct in computing for the overall heat transfer coefficient, the one with Area involved in the formula or not?
![Overall heat transfer coefficient =
3.42417
= 0.2920](https://content.bartleby.com/qna-images/question/8b13c60b-8d18-4823-b8e9-108515c0302b/ad53a118-78fb-423d-b03e-1ee554a2b202/lc0bgaj_thumbnail.png)
Transcribed Image Text:Overall heat transfer coefficient =
3.42417
= 0.2920
![Overall heat transfer coefficient of the system.
QUAAT
Q
AXAT
1. U =
6.133
(1.06x1.3)x(33-12)
|U= 0.21194 KW/m²+k](https://content.bartleby.com/qna-images/question/8b13c60b-8d18-4823-b8e9-108515c0302b/ad53a118-78fb-423d-b03e-1ee554a2b202/7287esx_thumbnail.png)
Transcribed Image Text:Overall heat transfer coefficient of the system.
QUAAT
Q
AXAT
1. U =
6.133
(1.06x1.3)x(33-12)
|U= 0.21194 KW/m²+k
Solution
Follow-up Question
Why did you divide by 2 the thermal conductivity of E,F,B and C? Why not use parallel resistance calculation instead?
Solution
Follow-up Question
Why did you not use the area for computing the overall heat transfer coefficient
Solution
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