Q4. A series circuit comprises an inductor, of resistance 10 Q and inductance 159 pH, and a variable capacitor connected to a 50 mV sinusoidal supply of frequency 1 MHz. What value of capacitance will result in resonant conditions and what will then be the current? For what values of capacitance will the current at this frequency be reduced to 10 per cent of its value at resonance? Q4. A series circuit comprises an inductor, of resistance 10 Q and inductance159 µH, and a variable capacitor connected to a 50 mV sinusoidal supply offrequency 1 MHz. What value of capacitance will result in resonantconditions and what will then be the current? For what values of capacitancewill the current at this frequency be reduced to 10 per cent of its value atresonance?

To solve above problem, one should have basic idea about working of AC circuits. Above given circuit…

Answered: A series circuit comprises an inductor,…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Q4. A series circuit comprises an inductor, of resistance 10 Q and inductance 159 pH, and a variable capacitor connected to a 50 mV sinusoidal supply of frequency 1 MHz. What value of capacitance will result in resonant conditions and what will then be the current? For what values of capacitance will the current at this frequency be reduced to 10 per cent of its value at resonance?

Q4. A series circuit comprises an inductor, of resistance 10 Q and inductance
159 µH, and a variable capacitor connected to a 50 mV sinusoidal supply of
frequency 1 MHz. What value of capacitance will result in resonant
conditions and what will then be the current? For what values of capacitance
will the current at this frequency be reduced to 10 per cent of its value at
resonance?

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Hello I am really confused how you have simplified down the Z value down to the C= 176.931 I would like the clear steps please as it just shows the equation and jumps to the answer. Thank you.

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