CIRCLE EACH ANSWER ### Hydrostatic Force on a Submerged Semicircular Plate**Problem Statement:**A semicircular plate with a radius of 9 meters is submerged vertically in water so that the top is 1 meter above the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s² for the acceleration due to gravity. Recall that the mass density of water is 1000 kg/m³.)**Integral Expression:**\[ 2 \rho g \int_{0}^{9 - 1} (\sqrt{9^2 - x^2}) x \, dx \]where:- \(\rho = 1000 \) kg/m³ (mass density of water)- \(g = 9.8 \) m/s² (acceleration due to gravity)- \(x\) ranges from the top to the bottom of the submerged plate**Diagram Description:**The diagram illustrates a semicircular plate fully submerged in water with a portion extending 1 meter above the water surface. The depth is denoted \(x\) and the horizontal span is \( \sqrt{9^2 - x^2} \), representing the distance across the plate at a depth \(x\).### Analytical Approach:1. **Hydrostatic Pressure Calculation:** \[ P = \rho g h \] where \(h\) is the depth below the water surface.2. **Force Calculation:** The differential force \(dF\) on a thin strip at depth \(x\): \[ dF = P \cdot dA \] where \(dA\) is the area of the strip. \[ dA = 2 (\sqrt{9^2 - x^2}) \cdot dx \] Hence: \[ dF = \rho g x \cdot 2 (\sqrt{9^2 - x^2}) \cdot dx \]3. **Integral Setup:** \[ F = 2 \rho g \int_{0}^{8} (\sqrt{9^2 - x^2}) x \, dx \]**Evaluate the Integral:**The solution involves integrating the function over the given limits and then multiplying by

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A semicircular plate with radius 9 m is submerged vertically in water so that the top is 1 m above the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s? for the acceleration due to gravity. Recall that the mass density of water is 1000 kg/m.) N