A screen is placed a distance d = 42.0 cm to the right of a small object. At what two distances to the right of the object can a converging lens of focal length +S,80 cm be placed if the real image of the object is at the location of the screen? sf s-f (Hint: Use the thin lens equation in the form s'= so s's - ) = sf. Write s'= d-s and solve for s in the resulting quadratic equation.) shorter distance 139 41 862 X cm longer distance X cm For this lens, what is the smallest value d can have and an image be formed on the screen? 232 cm Additional Materials Thin Lenses
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- a) You are holding a convex lens at arm's length and looking at a distant street-light. You observe the up-side down image of the street light to be on your side of the lens and 60.0 mm from the lens. You then train the lens on your study lamp. If your study lamp is 100.0 mm from the lens, how far will the image of the lamp be from the lens (in mm)? b)If your study lamp bulb is spherical of diameter 27.0 mm, what will be the diameter of its image (in mm)?A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 8.30 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position height cm cm -Select- -Select- Is the image real or virtual? O real O virtual in front of the second lens behind the second lens Is the image inverted or upright? O upright O inverted 4HW8 Q10 A magnifying glass is a single convex lens with a focal length of f= 13.0 cm. What is the angular magnification when this lens forms a (virtual) image at −∞? How far from the object should the lens be held? What is the angular magnification when this lens forms a (virtual) image at the person's near point (assumed to be 25 cm)? How far from the object should the lens be held in this case?
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