**Solubility Curves Practice**The graph depicts solubility curves for various salts, showing how solubility (expressed in grams of salt per 100 grams of water) varies with temperature (in degrees Celsius). The curves represent the following substances:- NaNO₃ (Sodium Nitrate)- CaCl₂ (Calcium Chloride)- Pb(NO₃)₂ (Lead(II) Nitrate)- KNO₃ (Potassium Nitrate)- KCl (Potassium Chloride)- NaCl (Sodium Chloride)- KClO₃ (Potassium Chlorate)- K₂Cr₂O₇ (Potassium Dichromate)- Ce₂(SO₄)₃ (Cerium(III) Sulfate)**Questions:**1. A saturated solution of potassium nitrate dissolved in 250 grams of water is cooled from 50 °C to 10 °C. How many grams of potassium nitrate will be precipitated out of the solution as it cools?2. 180 grams of lead (II) nitrate is added to 300 grams of water at 10 °C. To what temperature must the solution be raised in order to have a saturated solution with NO EXCESS solid lead (II) nitrate present?3. How many grams of potassium chlorate must be added to 270 grams of water in order to have a saturated solution of potassium chlorate at 60 degrees Celsius?4. If 285 grams of sodium chloride are put into 300 grams of water at 40 °C and stirred, will the solution be saturated, supersaturated, and unsaturated?5. Which substance is the most soluble at 10 °C?6. 100 mL of water at 50 degrees Celsius can hold _____ grams of potassium chloride.7. 100 mL of water at 80 degrees Celsius can hold _____ grams of potassium chlorate.8. How many grams of sodium nitrate will precipitate out of a 100-mL solution of sodium nitrate if the solution is cooled from 80 degrees Celsius to 30 degrees Celsius?9. If 50 grams of potassium chloride are dissolved in 100 mL of water at 55 degrees Celsius, will the solution be saturated, supersaturated, or unsaturated?10. At 40 degrees Celsius, how much Potassium Nitrate will dissolve in 500 g of water?

Hi and thanks for the question. Since you have posted multiple questions and have not specified which question is to be answered, we will answer the first question for you. If you need help with any specific question please post the question mentioning that question.1) Mass of water = 250 g Initial Temperature T1 = 50oC Final Temperature T2 = 10oC From the Solubility curve of Potassium Nitrate KNO3 The solubility of KNO3 in the water at T1 = 50oC = 88 g KNO3100 g H2O The solubility of KNO3 in the water at T2 = 10oC = 20 g KNO3100 g H2OAmount of KNO3 that water can hold at 50oC = 88 g KNO3100 g H2O × 250 g H2O = 220 g KNO3 Amount of KNO3 that water can hold at 10oC = 20 g KNO3100 g H2O × 250 g H2O = 50 g KNO3 Amount of KNO3 precipitated = 220 - 50 = 170 g