A saturated aqueous solution of CDF2 is prepared. The equilibrium in the solution is represented above. In the solution, [Cd2+ 0.90 M NaF is added to the saturated solution. Which of the following identifies the molar solubility of CdF, in pure water and explains the effect that the addition of NaF 0.0585 M and [F = 0.117 M. Some has on this solubility?
A saturated aqueous solution of CDF2 is prepared. The equilibrium in the solution is represented above. In the solution, [Cd2+ 0.90 M NaF is added to the saturated solution. Which of the following identifies the molar solubility of CdF, in pure water and explains the effect that the addition of NaF 0.0585 M and [F = 0.117 M. Some has on this solubility?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:CdF2 (s) 2 Cd+ (ag) + 2 F (aq)
A saturated aqueous solution of CDF2 is prepared. The equilibrium in the solution is represented above. In the solution, CdTeo
0.90 M NaF is added to the saturated solution. Which of the following identifies the molar solubility of CdF, in pure water and explains the effect that the addition of NaF
= 0.0585 M and [F = 0.117 M. Some
has on this solubility?
The molar solubility of CDF2 in pure water is 0.0585 M, and adding NaF decreases this solubility because the equilibrium shifts to favor the precipitation of
A
some CDF2.
The molar solubility of CDF2 in pure water is 0.0585 M, and adding NaF has no effect on the solubility because only changes in temperature can increase or
decrease the molar solubility of an ionic solid.
The molar solubility of CdF, in pure water is 0.117 M, and adding NaF decreases this solubility because the equilibrium shifts to favor the precipitation of
C
some CDF2.
The molar solubility of CdF2 in pure water is 0.176 M, and adding NaF increases this solubility because the Na ions displace the Cd ions, causing the
equilibrium to shift to favor the products.
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