A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite staysover a fixed point on the equator). Use Kepler’s Third Law to showthat in a circular geosynchronous orbit, the distance from the center ofthe earth is R ≈ 42,246 km. Then compute the altitude h of the orbitabove the earth’s surface. The earth has mass M ≈ 5.974 × 1024 kgand radius R ≈ 6371 km.

Q: A satellite is orbiting around a planet with a mass of 6.0 x 1024kg and a radius of 6.0 x 106m.  If…

A: Let G, M, m, r, and v denote the gravitational constant, planet’s mass, satellite’s mass, orbital…

Q: Determine the height habove the surface of a planet of radius R and mass M at which the…

A: The gravitational field will be 60% on its surface, gh=g×60100=35g Then, weight of a mass on the…

Q: (a) Calculate the work (in MJ) necessary to bring a 104 kg object to a height of 991 km above the…

A: Given that: The mass of an object is m=104 kg The earth's mass is M=5.97×1024 kg The height is h=991…

Q: A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits…

A: To solve this problem we use the concept of Kepler's third law.  Let us consider the mass of earth…

Q: In fact, the actual orbit that the GS entered was slightly elliptical, with its closest approach to…

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Q: In order better to map the surface features of the Moon, a 361 kgimaging satellite is put into…

A: Given Mass (m)             = 361 kg Radius (R)           = 1740 km Moon mass (M)  = 7.36×1022 kg…

Q: A satellite of mass 175 kg is launched from a site on Earth's equator into an orbit at 180 km above…

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Q: A satellite is in a circular orbit around the Earth at an altitude of 3.70  106 m. (a) Find the…

A: The solution to the problem (a) can be given by considering Kepler's third laws of motion, which…

Q: A satellite is given a boost of 595 MJ of energy to move it from its initial orbit at an altitude of…

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Q: Suppose an asteroid named Sparty has been discovered revolving around the Sun on a circular orbit…

A: Here, the gravitational force acts as centripetal force So: mv2R=GMmR2i.e.v=GMRAnd also as v=2πRT…

Q: According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is…

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Q: A 799-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean…

A: mass of satellite, m =799 Kg Mass of earth, M= 5.97 x 1024kg Radius of earth= 6372 x 103 m radius of…

Q: A satellite is in a circular orbit around the Earth at an altitude of 3.36 x 10 m. (a) Find the…

A: Given data The altitude of the satellite from the earth is given as r = 3.36 x 106 m. a) The time…

Q: An Earth satellite has an orbital period of 5.3 h. What is its orbital radius? (ME = 5.98 x 1024 kg)

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Q: The Earth has a mass of 5.974 x 10^24 kg. The NSS-6 Earth orbiting satellite has a mass of 4,575 kg…

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Q: Calculate the period of a satellite orbiting a planet with the mass 8.7 x 1022 kg given the height…

A: Mass of the planet, M=8.7×1022kg Height to the satellite's orbit, h=300km=300×103m Radius of the…

Q: A satellite is in a circular orbit around the Earth at an altitude of 2.70 x 10° m. (a) Find the…

A: Given that a satellite is in a circular orbit around the earth at an altitude of 2.70 * 10^6metre.…

Q: why this statement is not accurate. "The gravitational force of the planet on a satellite in…

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Q: A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours…

A: Given values:- Time period,(T)=24 Hr=24 x 3600 sec=86400 sec ----(1) Distance from the center of the…

Q: The radius of the Earth may be taken to be 6,371 km. Assume a satellite is in orbit at an altitude…

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Q: Calculate the eccentricity, e, of a planet's orbit around a central star if the ratio of its…

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Q: The mean radius of earth from the Sun is 0.67 times the mars mean distancxe of mars from the sun.…

A: given that, The mean radius of earth from the Sun is 0.67 times the mars mean distance of mars from…

Q: Two planets P, and P, orbit around a star S in circular orbits with speeds v, = 44.4 km/s, and v,…

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Q: A communications satellite is launched into circular orbit around the Earth, at an altitude h. The…

A: a) Write the equation of Kepler’s third law.

Q: A satellite is in a circular orbit around the Earth at an altitude of 1.76  106 m. (a) Find the…

A: Given, A satellite is in a circular orbit around the earth at an altitude of, h = 1.76×106 m radius…

Q: A 765-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean…

A: ( b ) T = 2 πr / v ; T = 2 π* ( 2 * 6.4 e 6 ) / 5588.1 ; T = 14392.1497 s   T =14407 / 60 min =…

Q: On the ground level, the weight of a satellite is W N. The satellite is launched and stays in an…

A: On surface of the earth gravity is g = GMR2 , where R is radius of earth , G is gravitational…

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A:

Central Force

Central force is the force that acts along the center of mass of one body to the center of mass of another body. Its direction from or away from a point on a body to another is called the center of the force. Such forces include gravitational force between two massive objects or electrostatic forces between two charged particles. So from atoms to planets, the central forces play an important role in shaping our daily lives. One of the remarkable features of central forces is that they are conservative, i.e. the total energy of a central force system can always be expressed as a gradient of a potential energy function.