(a) Calculate the work (in MJ) necessary to bring a 104 kg object to a height of 991 km above the surface of the Earth. -854 X The work done must provide the increase in gravitational potential energy, so calculate AU, for the system. You will need the radius and mass of the Earth for your calculation. MJ (b) Calculate the extra work (in J) needed to launch the object into circular orbit at this height. 2.619E9 Notice that the centripetal force for the object in orbit is due to the gravitational force from the Earth. Write and equate two expressions for the force, in terms of Newton's universal law of gravitation and the centripetal force, and solve for v2. The additional work is equal to the kinetic energy, so find K using your value for v². J

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Description:**

*(a)* Calculate the work (in MJ) necessary to bring a 104 kg object to a height of 991 km above the surface of the Earth.

- **Incorrect Answer Provided:** -854 MJ
- **Feedback:** The work done must provide the increase in gravitational potential energy, so calculate \( \Delta U_g \) for the system. You will need the radius and mass of the Earth for your calculation.

*(b)* Calculate the extra work (in J) needed to launch the object into circular orbit at this height.

- **Incorrect Answer Provided:** 2.619E9 J
- **Feedback:** Notice that the centripetal force for the object in orbit is due to the gravitational force from the Earth. Write and equate two expressions for the force, in terms of Newton's universal law of gravitation and the centripetal force, and solve for \( v^2 \). The additional work is equal to the kinetic energy, so find \( K \) using your value for \( v^2 \).
Transcribed Image Text:**Problem Description:** *(a)* Calculate the work (in MJ) necessary to bring a 104 kg object to a height of 991 km above the surface of the Earth. - **Incorrect Answer Provided:** -854 MJ - **Feedback:** The work done must provide the increase in gravitational potential energy, so calculate \( \Delta U_g \) for the system. You will need the radius and mass of the Earth for your calculation. *(b)* Calculate the extra work (in J) needed to launch the object into circular orbit at this height. - **Incorrect Answer Provided:** 2.619E9 J - **Feedback:** Notice that the centripetal force for the object in orbit is due to the gravitational force from the Earth. Write and equate two expressions for the force, in terms of Newton's universal law of gravitation and the centripetal force, and solve for \( v^2 \). The additional work is equal to the kinetic energy, so find \( K \) using your value for \( v^2 \).
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