A satellite is in a circular orbit 380 km above the Earth's surface. Find the orbital period and the speed of the satellite. Take MEarth = 5.97×1024 kg, REarth = 6,371 km. The orbital period, T = Units Select an answer ✓ The orbital speed, v = How high above the Earth's surface should be the orbit of a satellite so it's orbital period equals to the period of the Earth's spin (24 hrs)? The elevation above the surface, h = Units Select an answer Units Select an answer ✓

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A satellite is in a circular orbit 380 km above the Earth's surface. Find the orbital period and the speed of
the satellite. Take MEarth = 5.97×1024 kg, REarth = 6,371 km.
The orbital period, T =
Units Select an answer ✓
The orbital speed, v =
How high above the Earth's surface should be the orbit of a satellite so it's orbital period equals to the
period of the Earth's spin (24 hrs)?
The elevation above the surface, h =
Units Select an answer ✓
Units Select an answer ✓
Transcribed Image Text:A satellite is in a circular orbit 380 km above the Earth's surface. Find the orbital period and the speed of the satellite. Take MEarth = 5.97×1024 kg, REarth = 6,371 km. The orbital period, T = Units Select an answer ✓ The orbital speed, v = How high above the Earth's surface should be the orbit of a satellite so it's orbital period equals to the period of the Earth's spin (24 hrs)? The elevation above the surface, h = Units Select an answer ✓ Units Select an answer ✓
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