A sample of size n=150 is to be used to test the following hypothesis at the level of significance0.02.HO: mu = 8.3 versus Ha: mu is not equal to 8.3,where mu is the true average weight of a newborn American baby. Give the appropriate rejectionregion.Let T = (bar{X}- mu) / (S/sqrt{n})where, bar{X} = sample mean and sqrt{n} is the square root of n.OT> 2.575 or T< -2.575OT> 2.325 or T < -2.325OT> 1.96 or T< -1.96 Historically, the average time it takes Klm to swim the 200 meter butterfly is 148.4 seconds. Kimwould like to know if her average time has changed. She records her time on 50 randomly selectedoccasions and computes the mean to be 147.8 with a standard deviation of 2.3 seconds. Determinethe null and alternative hypothesis, and your conclusion at the level of significance .01.O HO: mu = 148.4 v.s. Ha: mu is not equal to 148.4T= (bar{X} - mu) / (S/sqrt{n})Since the observed value of the test statistics T_{obs} = -1.845 and |T_{obs}| < 2.575, we cannot reject HO.O HO: mu = 148.4 v.s. Ha: mu > 148.4T= (bar{X} - mu) / (S/sqrt{n})Since the observed value of the test statistics T_{obs} = -1.845 and T_{obs} < 2.325, we cannot reject HO.O HO: mu = 148.4 v.s. Ha: mu < 148.4T = (bar{X} - mu) / (S/sqrt{n})Since the observed value of the test statistics T_{obs} = -1.845 and T_{obs} > - 2.325, we cannot reject HO.

Name: A sample of size n=150 is to be used to test the following hypothesis
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A sample of size n=150 is to be used to test the following hypothesis at the level of significance0.02.HO: mu = 8.3 versus Ha: mu is not equal to 8.3,where mu is the true average weight of a newborn American baby. Give the appropriate rejectionregio

“Since you have asked multiple questions, we will solve the first question for you. If you want any…

Math

Statistics

A sample of size n=150 is to be used to test the following hypothesis at the level of significance 0.02. HO: mu = 8.3 versus Ha: mu is not equal to 8.3, where mu is the true average weight of a newborn American baby. Give the appropriate rejection region. Let T (bar{X}- mu) / (S/sqrt{n}) where, bar{X} = sample mean and sqrt{n} is the square root of n. OT> 2.575 or T< -2.575 OT> 2.325 or T< -2.325 OT> 1.96 or T< -1.96

A sample of size n=150 is to be used to test the following hypothesis at the level of significance 0.02. HO: mu = 8.3 versus Ha: mu is not equal to 8.3, where mu is the true average weight of a newborn American baby. Give the appropriate rejection region. Let T (bar{X}- mu) / (S/sqrt{n}) where, bar{X} = sample mean and sqrt{n} is the square root of n. OT> 2.575 or T< -2.575 OT> 2.325 or T< -2.325 OT> 1.96 or T< -1.96

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A sumple from a normal population with mu = 50 and sigma = 6 of M=48.20, . the sample mean.corresponds to tz = - 1.50 , then how many scores are in the sample?
The mean score on a driving exam for a group of driver's education students is 60 points, with a standard deviation of 3 points. Apply Chebychev's Theorem to the data using k=2. Interpret the results. At least ( )% of the exam scores fall between ( )and ( )
I need letter d. Thank you!
An obstetrician read that a newborn baby loses on average 7 ounces in the first two days of his or her life. He feels that in the hospital where he works, the average weight loss of a newborn baby is less than 7 ounces. A random sample of 30 newborn babies has a mean weight loss of 6.4 ounces. The population standard deviation is 1.6 ounces. Is there enough evidence at =α0.01 to support his claim? Assume that the variable is normally distributed. Use the critical value method with tables. hello the question askas to find the critical value compute the test value and select the hypothesis
GPAS at CCSU are normally distributed with a mean of 2.14 and a standard deviation of 0.52. Find the z-score for a GPA of 2.78.
The average height X and weight Y of males in population have a bivariate normal distribution with means µX 1.80 m., µy 90.0 kgs and standard deviations Ox = 0.30 m., oy = 15.3 kgs respectively. The correlation coefficient between X and Y is p= 0.80.
Total fat content (including saturated fat and trans fats) is a key characteristic of cheese. Assume that for a given type of cheese, total fat content (10-1 g/g of cheese) follows a normal distribution with a population mean of 2.85 (unit) and a population variance of 0.01 (unit2). Such an assumption is reasonable because fat content varies inside cheese and the “errors” around the mean total fat content (i.e. the value appearing on the etiquette) are distributed like a bell shape. a) What is the probability that the total fat content of this cheese exceeds 3 (unit)? b) What is the probability that the total fat content varies from 2.8 to 3 (unit)?
The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) u and standard deviation o = 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 15 cigarettes of this brand. The sample yields an average of 1.6 mg of nicotine. Conduct a test using a significance level of a = 0.05. (a) The standardized test statistic (b) The critical value (endpoint of Rejection Region) is z* = (c) The final conclusion is OA. The nicotine content is probably higher than advertised. B. There is not sufficient evidence to show that the ad is misleading.
GPAs at CCSU are normally distributed with a mean of 2.25 and a standard deviation of 0.45. Find the z-score for a GPA of 2.49.