A sample of n=25 individuals is randomly selected from a population with a mean of p=65, and a treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be 70. If the sample standard deviation is s=20, the data is sufficient enough to conclude that the treatment has a significant effect using a two-tailed test with alpha level of 0.05, or that you conclude that you reject your null hypothesis. You have to do the 4-step hypothesis testing procedure to determine the answer to this item. Select one: O True O False
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- The manufacturer claims that your new car gets 35 mpg on the highway. You suspect that the mpg is a different number for your car. The 66 trips on the highway that you took averaged 40.4 mpg and the standard deviation for these 66 trips was 13.7 mpg. What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly different from 35 at αα = 0.01, so there is statistically insignificant evidence to conclude that the sample mean mpg for your car on the highway is different from 40.4. The data suggest that the populaton mean is significantly different from…The manufacturer claims that your new car gets 31 mpg on the highway. You suspect that the mpg is less for your car. The 57 trips on the highway that you took averaged 28.8 mpg and the standard deviation for these 57 trips was 10.7 mpg. What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest that the populaton mean is significantly less than 31 at αα = 0.01, so there is statistically significant evidence to conclude that the population mean mpg for your car on the highway is less than 31. The data suggest that the population mean is not significantly less than 31 at αα = 0.01, so there…Has the Percentage of U.S. Adults Who Smoke Decreased since 2007? With data from the 2005-2007 National Health Interview Survey, the Centers for Disease Control and Prevention estimated that about 20% of U.S. adults (18 and older) smoke. Is the percentage lower this year? Suppose we select a random sample of 100 adults (18 and older) this year. The conditions are met for use of a normal model, because we expect 20 smokers (20% of 100) in the sample and 80 nonsmokers. Both expected counts are greater than 10, so we use a z-score and a standard normal curve to assess the evidence. (The standard error is 0.04.) Suppose that 15 in our sample of 100 are smokers. Which conclusion is supported by the data? We cannot conclude that the percentage of U.S. adults (18 and older) who smoke is less than 20% this year. We can conclude that the percentage of U.S. adults (18 and older) who smoke is less than 20% this year. Incorrect. You are right that the percentage in the sample is 15% and this is…
- The manufacturer claims that your new car gets 26 mpg on the highway. You suspect that the mpg is more for your car. The 48 trips on the highway that you took averaged 30.4 mpg and the standard deviation for these 48 trips was 9.4 mpg. What can be concluded at the αα = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis.A professor wants to make sure that two different versions of a test are equivalent. He decides to compare the variances of the test scores from each version. A sample of 20 scores on Version A has a sample variance of 1.139, while a sample of 25 scores from Version B has a sample variance of 3.958. Step 1 of 2 : Construct a 99% confidence interval for the ratio of the population variances of the scores on the two versions of the test. Round the endpoints of the interval to four decimal places, if necessary. Step 2 of 2 Interpret the confident interval obtained on Step 1:You wish to test the following claim (HaHa) at a significance level of α=0.001α=0.001. Ho:μ=51.3Ho:μ=51.3 Ha:μ≠51.3Ha:μ≠51.3You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=12n=12 with mean M=49.2M=49.2 and a standard deviation of SD=5.5SD=5.5.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = CorrectWhat is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = Incorrect0.2128 or 0.2127The p-value is... less than (or equal to) αα greater than αα Correct This test statistic leads to a decision to... reject the null accept the null fail to reject the null Correct As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 51.3. There is not sufficient evidence to warrant rejection of the claim that the population mean is…
- You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly different from 0.14. You use a significance level of α=0.10α=0.10. H0:p=0.14H0:p=0.14 H1:p≠0.14H1:p≠0.14You obtain a sample of size n=345n=345 in which there are 69 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... The sample data support the claim that the proportion of men over 50 who regularly have their prostate examined is different from 0.14. There is not sufficient sample evidence to support the claim that the proportion of men over 50 who regularly have their prostate…You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly different from 0.44. You use a significance level of α=0.05α=0.05. H0:p=0.44H0:p=0.44 H1:p≠0.44H1:p≠0.44You obtain a sample of size n=298n=298 in which there are 153 successes.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This p-value leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is different from 0.44. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is different from 0.44. The sample data support the claim that the…You wish to test the following claim (HaHa) at a significance level of α=0.02α=0.02. Ho:μ=55.8Ho:μ=55.8 Ha:μ>55.8Ha:μ>55.8You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=29n=29 with a mean of M=68.4M=68.4 and a standard deviation of SD=18.3SD=18.3.What is the critical value for this test? ***(Report answer accurate to three decimal places.)***critical value = What is the test statistic for this sample? **(Report answer accurate to three decimal places.)** test statistic = The test statistic is... in the critical region not in the critical region This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 55.8. There is not sufficient evidence to warrant rejection of the claim that the population mean…
- A company that makes basketballs has the motto, "Our basketballs are ready to play." Therefore, it is important to the company that the basketballs are inflated with the proper amount of air when shipped. Most basketballs are inflated to 7 to 9 pounds per square inch. From a set of calibration data, X = 8.03 and R=0.57. Recently the company selected a random basketball from its production line at four different time periods over its normal production day. The results were listed in the accompanying table. Complete parts a through c. Click the icon to view the data table. Click the icon to view the factors for calculating control limits. a) Create an x-bar chart based on the calibration data statistics for these 6 samples. Choose the correct graph below. OA. O B. 2 3 4 5 6 Group 1.6-1 1.2- 0.8- 0.4- 1 2 3 4 5 Group 6 Q UCL CL LCL Q Ucha CL 8.6 8.4- b) Create an R chart based on the calibration data statistics for these 6 samples. Choose the correct graph below. O A. O B. LCL 8.24 8 7.8…You wish to test the following claim (HaHa) at a significance level of α=0.001α=0.001. Ho: μ = 57.2 Ha: μ < 57.2You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=106n=106 with a mean of μ=56.2μ=56.2 and a standard deviation of s=9.8s=9.8.What is the critical value for this test? (Report answer accurate to three decimal places.) critical value = ________10% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 369 people from the inner city surveyed, 22 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: Ho: ? μ p Select an answer = < ≠ > (please enter a decimal) H1: ? μ p Select an answer > ≠ < = (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 10% at αα = 0.01, so…