A sample of N203(g) has a pressure of 0.058 atm. The temperature (in K) is then doubled and the N203 undergoes complete decomposition to NO2(g) and NO(g). Find the total pressure of the mixture of gases assuming constant volume and no additional temperature change.
A sample of N203(g) has a pressure of 0.058 atm. The temperature (in K) is then doubled and the N203 undergoes complete decomposition to NO2(g) and NO(g). Find the total pressure of the mixture of gases assuming constant volume and no additional temperature change.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A sample of N2O3{g) has a pressure of 0.058 atm. The temperature (in K) is then doubled and
the N203 undergoes complete decomposition to NO2(g) and NO(g).
Find the total pressure of the mixture of gases assuming constant volume and no additional
temperature change.
Enter your answer numerically, in terms of atm.
Expert Solution

Step 1
The initial pressure is 0.058 atm, when temperature is doubled then pressure will increase.
lets initial temperature is K1 and final temperature is K2 then it is given that
K2=2K1
P1=0.058 atm
P2=?
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