A sample of male and female students were equipped with a device that records sound for one day. Data about number of words spoken per day are presented below: Mean Standard Deviation Males (n=56) 16177 7520 Answer the following: 1. Upper Limit 2. Lower Limit Females (n=56) 16569 9108 Construct a 99% confidence interval for the difference in the mean number of words spoken by males and females. Assume the population variances to be unknown and unequal.
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- Click to see additional instructions The interval [40 50] represents a 90% confidence interval for a population mean. What is the most likely value for the sample mean, xbar?Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1018 and x = 550 who said "yes." Use a 90% confidence level. %3D Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. D E = (Round to three decimal places as needed.) c) Construct the confidence interval.Janet wants to estimate the percentage of people who have been required to take a drug test for work. She surveys 250 individuals and finds that 175 have taken a drug test for work. Identify the values needed to calculate a confidence interval at the 98% confidence level. Then use Excel to find the confidence interval. Round the final answer to three decimal places. Provide your answer below:A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=935 and x=561 who said "yes." Use a 95% confidence level.A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our…Use the sample data and confidence level given below to complete parts (a) through (d). K A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1100 and x = 501 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. 10 on 11 me solve this "1 a) Find the best point estimate of the population proportion p. 0 (Round to three decimal places as needed.) View an example Get more help. on 5858 409 x PROV H command % 3 a w ER T Q ER AL G SDFO C с MacBook Air T II B U N M K O 38 Clear all cfnm P ? I command alt optionneed help pleaseEducational Television In a random sample of 205 people, 14 said that they watched educational television. Find the 99% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.A survey was conducted two years ago asking college students their top motivations for using a credit card. You think this distribution has changed. You randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the distribution? Use a = 0.025. Complete parts (a) through (d). Response Old Survey % 29% New Survey Frequency, f Rewards 110 Low rates Cash back Discounts 23% 96 21% 109 7% 46 Other 20% 64 O B. The distribution of motivations is 110 rewards, 96 low rate, 109 cash back, 46 discounts, and 64 other. O C. The distribution of motivations is 29% rewards, 23% low rate, 21% cash back, 7% discounts, and 20% other. Which hypothesis is the claim? o Ho (b) Determine the critical value, Yo, and the rejection region. X = 11.143 (Round to three decimal places as needed.) Choose the correct rejection region below. Oc. Xok In a survey of 2279 adults, 720 say they believe in UFOs. Construct a 95% confidence interval for the population proportion of adults who believe in UFOs. A 95% confidence interval for the population proportion is (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. R OA. With 95% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. OB. With 95% probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval. OC. With 95% confidence, it can be said that the sample proportion of adults who believe in UFOs is between the endpoints of V C ◎可 F5 J % 250 T F6 دار 6 & X F7 & 7 N 8 F8 J 00 * 8 8 F9 M 09 9 K F10 O V 70°F Sunny A ☀- F11 O Alt ☀ P + F12 ^ Next 1:23 PM 11/23/2022 PrtSc CM +11 InseA new fertilizer was applied to the soil of 246 bean plants. 25% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage):Confidence Interval: % to %Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=972 and x = 577 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. 0.594 (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = 0.041 (Round to three decimal places as needed.) c) Construct the confidence interval.SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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