### Optical Activity and Enantiomeric Excess of LimoneneA sample of limonene is analyzed to have a specific rotation of +75.9°. The specific rotations of the individual isomers are as follows:- \( R \)-(+)-limonene: \([\alpha]_D = +125.6°\)- \( S \)-(-)-limonene: \([\alpha]_D = -122.1°\)#### Calculate the Percent Enantiomeric Excess (% ee)To find the percent enantiomeric excess, use the following formula:\[\% ee = \left(\frac{\text{observed rotation}}{\text{rotation of pure enantiomer}}\right) \times 100\]#### Determine the Molecular CompositionThe molecular composition can be found by determining the percentages of the \( S \) and \( R \) isomers in the sample.- Calculate the percentage of the \( S \) isomer: \[ \% \text{ of } S \text{ isomer: } \_\_\_\_ \]- Calculate the percentage of the \( R \) isomer: \[ \% \text{ of } R \text{ isomer: } \_\_\_\_ \]### NOTEThese calculations help in understanding the chiral purity and composition of the limonene sample, which is crucial in various applications such as flavoring, fragrance, and pharmaceutical industries.

enantiomer are pair of isomer which bear mirror image relationship but are non superimposable

A sample of limonene has a specific rotation of +75.9°. R-(+)-limonene [a]p = +125.6° and S-(-)-limonene [a]p = -122.1°. What is the percent enantiomercic excess (% ee)? % ee: What is the molecular composition of this same sample? percent of S isomer: percent of R isomer:

A sample of limonene has a specific rotation of +75.9°. R-(+)-limonene [a]p = +125.6° and S-(-)-limonene [a]p = -122.1°. What is the percent enantiomercic excess (% ee)? % ee: What is the molecular composition of this same sample? percent of S isomer: percent of R isomer:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

### Optical Activity and Enantiomeric Excess of Limonene

A sample of limonene is analyzed to have a specific rotation of +75.9°. The specific rotations of the individual isomers are as follows:

- \( R \)-(+)-limonene: \([\alpha]_D = +125.6°\)
- \( S \)-(-)-limonene: \([\alpha]_D = -122.1°\)

#### Calculate the Percent Enantiomeric Excess (% ee)

To find the percent enantiomeric excess, use the following formula:

\[
\% ee = \left(\frac{\text{observed rotation}}{\text{rotation of pure enantiomer}}\right) \times 100
\]

#### Determine the Molecular Composition

The molecular composition can be found by determining the percentages of the \( S \) and \( R \) isomers in the sample.

- Calculate the percentage of the \( S \) isomer:

\[
\% \text{ of } S \text{ isomer: } \_\_\_\_
\]

- Calculate the percentage of the \( R \) isomer:

\[
\% \text{ of } R \text{ isomer: } \_\_\_\_
\]

### NOTE
These calculations help in understanding the chiral purity and composition of the limonene sample, which is crucial in various applications such as flavoring, fragrance, and pharmaceutical industries.

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