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A sample of limonene has a specific rotation of +75.9°. R-(+)-limonene [a]p = +125.6° and S-(-)-limonene [a]p = -122.1°. What is the percent enantiomercic excess (% ee)? % ee: What is the molecular composition of this same sample? percent of S isomer: percent of R isomer:

A sample of limonene has a specific rotation of +75.9°. R-(+)-limonene [a]p = +125.6° and S-(-)-limonene [a]p = -122.1°. What is the percent enantiomercic excess (% ee)? % ee: What is the molecular composition of this same sample? percent of S isomer: percent of R isomer:

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### Optical Activity and Enantiomeric Excess of Limonene A sample of limonene is analyzed to have a specific rotation of +75.9°. The specific rotations of the individual isomers are as follows: - \( R \)-(+)-limonene: \([\alpha]_D = +125.6°\) - \( S \)-(-)-limonene: \([\alpha]_D = -122.1°\) #### Calculate the Percent Enantiomeric Excess (% ee) To find the percent enantiomeric excess, use the following formula: \[ \% ee = \left(\frac{\text{observed rotation}}{\text{rotation of pure enantiomer}}\right) \times 100 \] #### Determine the Molecular Composition The molecular composition can be found by determining the percentages of the \( S \) and \( R \) isomers in the sample. - Calculate the percentage of the \( S \) isomer: \[ \% \text{ of } S \text{ isomer: } \_\_\_\_ \] - Calculate the percentage of the \( R \) isomer: \[ \% \text{ of } R \text{ isomer: } \_\_\_\_ \] ### NOTE These calculations help in understanding the chiral purity and composition of the limonene sample, which is crucial in various applications such as flavoring, fragrance, and pharmaceutical industries.
Transcribed Image Text:### Optical Activity and Enantiomeric Excess of Limonene A sample of limonene is analyzed to have a specific rotation of +75.9°. The specific rotations of the individual isomers are as follows: - \( R \)-(+)-limonene: \([\alpha]_D = +125.6°\) - \( S \)-(-)-limonene: \([\alpha]_D = -122.1°\) #### Calculate the Percent Enantiomeric Excess (% ee) To find the percent enantiomeric excess, use the following formula: \[ \% ee = \left(\frac{\text{observed rotation}}{\text{rotation of pure enantiomer}}\right) \times 100 \] #### Determine the Molecular Composition The molecular composition can be found by determining the percentages of the \( S \) and \( R \) isomers in the sample. - Calculate the percentage of the \( S \) isomer: \[ \% \text{ of } S \text{ isomer: } \_\_\_\_ \] - Calculate the percentage of the \( R \) isomer: \[ \% \text{ of } R \text{ isomer: } \_\_\_\_ \] ### NOTE These calculations help in understanding the chiral purity and composition of the limonene sample, which is crucial in various applications such as flavoring, fragrance, and pharmaceutical industries.
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