hellllllppppp me pls mixture?3.A sample of KHP, KHC8HAO4, weighing 2.035 g is titrated with NaOH andbacktitrated with HCI. NaOH required = 23.20 mL; HCI required = 2.675 mL. Ifeach mL of HCl is equivalent () to 0.01600 g of Na20, what volume of 6.00 NNaOH must be added to 500 mL of above NAOH to bring it to 0.5000N?4.A sample of processed meat scrap weighing 4.000 g is digested withconcentrated H2SO4 and Hg(catalyst) until the N present has been converted toNH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a100-mL of H2SO4 ( 1mL = 0.01860 g Na2O). The excess acid requires 57.60 mL ofNaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate thepercentage protein in the meat scrapA 1.2 g sample of mixture of NAOH and NazCO3 containing inert impurities sdissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator thesolution turns colorless after the addition of 30.0 mL of the acid. Methyl orange isthen added and 12 mL more of the acid is required before this indicatorchanges color. What is the percentage of NaOH and of Na2CO3 in the sample ?5.

A sample of KHP, KHC8H&O4, weighing 2.035 g is titrated with NaOH and backtitrated with HCI. NaOH required = 23.20 mL; HCI required 2.675 mL. If each mL of HCI is equivalent () to 0.01600 g of Na20, what volume of 6.00 N NaOH must be added to 500 mL of above NaOH to bring it to 0.5000N? A sample of processed meat scrap weighing 4.000 g is digested with concentrated H2SO4 and Hg(catalyst) until the N present has been converted to NH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a 100-mL of H2SO4 ( 1mL 0.01860 g Na20). The excess acid requires 57.60 mL of NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate the percentage protein in the meat scrap A 1.2 g sample of mixture of NaOH and NA2CO3 containing inert impurities s dissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator the solution turns colorless after the addition of 30.0 mL of the acid. Methyl orange is then added and 12 mL more of the acid is required before this indicator changes color. What is the percentage of NaOH and of Na2CO3 in the sample ?

A sample of KHP, KHC8H&O4, weighing 2.035 g is titrated with NaOH and backtitrated with HCI. NaOH required = 23.20 mL; HCI required 2.675 mL. If each mL of HCI is equivalent () to 0.01600 g of Na20, what volume of 6.00 N NaOH must be added to 500 mL of above NaOH to bring it to 0.5000N? A sample of processed meat scrap weighing 4.000 g is digested with concentrated H2SO4 and Hg(catalyst) until the N present has been converted to NH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a 100-mL of H2SO4 ( 1mL 0.01860 g Na20). The excess acid requires 57.60 mL of NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate the percentage protein in the meat scrap A 1.2 g sample of mixture of NaOH and NA2CO3 containing inert impurities s dissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator the solution turns colorless after the addition of 30.0 mL of the acid. Methyl orange is then added and 12 mL more of the acid is required before this indicator changes color. What is the percentage of NaOH and of Na2CO3 in the sample ?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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