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A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring corrective action? Source: DF: Ss: MS: Test Stat, F: Critical F: P-Value: 0.001 0.001 Treatment: 5 0.005 0.6049 2.7361 0.6963 Error: 77 0.077 Total: 82 0.082 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. No, because the P-value is greater than the significance level. O B. Yes, because the P-value is greater than the significance level. OC. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level. Does the company have a problem requiring corrective action? O A. Yes, because it is not likely that the candies do not have equal mean weights. O B. No, because it is likely that the candies do not have equal mean weights. OC. Yes, because it is likely that the candies do not have equal mean weights. O D. No, because it is not likely that the candies do not have equal mean weights.

A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring corrective action? Source: DF: Ss: MS: Test Stat, F: Critical F: P-Value: 0.001 0.001 Treatment: 5 0.005 0.6049 2.7361 0.6963 Error: 77 0.077 Total: 82 0.082 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. No, because the P-value is greater than the significance level. O B. Yes, because the P-value is greater than the significance level. OC. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level. Does the company have a problem requiring corrective action? O A. Yes, because it is not likely that the candies do not have equal mean weights. O B. No, because it is likely that the candies do not have equal mean weights. OC. Yes, because it is likely that the candies do not have equal mean weights. O D. No, because it is not likely that the candies do not have equal mean weights.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring IS corrective action? Source: DF: s: MS: Test Stat, F: Critical F: P-Value: 0.6049 0.001 0.001 Treatment: 5 0.005 2.7361 0.6963 Error: 77 0.077 Total: 82 0.082 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. No, because the P-value is greater than the significance level. or B. Yes, because the P-value is greater than the significance level. O C. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level. Does the company have a problem requiring corrective action? it O A. Yes, because it is not likely that the candies do not have equal mean weights. SH is O B. No, because it is likely that the candies do not have equal mean weights. O C. Yes, because it is likely that the candies do not have equal mean weights. O D. No, because it is not likely that the candies do not have equal mean weights.
Transcribed Image Text:A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring IS corrective action? Source: DF: s: MS: Test Stat, F: Critical F: P-Value: 0.6049 0.001 0.001 Treatment: 5 0.005 2.7361 0.6963 Error: 77 0.077 Total: 82 0.082 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. No, because the P-value is greater than the significance level. or B. Yes, because the P-value is greater than the significance level. O C. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level. Does the company have a problem requiring corrective action? it O A. Yes, because it is not likely that the candies do not have equal mean weights. SH is O B. No, because it is likely that the candies do not have equal mean weights. O C. Yes, because it is likely that the candies do not have equal mean weights. O D. No, because it is not likely that the candies do not have equal mean weights.
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