A local bank claims that the waiting time for its customers to be served is the lowest in the area. A competitor bank checks the waiting times at both banks. The sample statistics are listed below. Test the local bank’s claim. Use the information given below. Use a significance level of .05 and assume the variances are equal.   Sample statistics for a local bank and a competitor's bank Sample size Local Bank n1=46 Competitor Bank n2=50 Average waiting time in minutes for each sample X¯¯¯1=2.3 mins. X2__ =2.6 Sample Standard Deviation of each Sample s1= 1.1 mins s2=1.0 mins. Are the samples dependent or independent? answered State your Null/Alternative hypotheses? Answered What is the test-statistic? Answered What is the p-value? answered What are the critical values? answered Does the test-statistic lie in the rejection region? answered Interpret the Result? Does the result change for a different value of alpha? Explain?

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A local bank claims that the waiting time for its customers to be served is the lowest in the area. A competitor bank checks the waiting times at both banks. The sample statistics are listed below. Test the local bank’s claim. Use the information given below. Use a significance level of .05 and assume the variances are equal.

 

Sample statistics for a local bank and a competitor's bank

Sample size

Local Bank

n1=46

Competitor Bank

n2=50

Average waiting time in minutes for each sample X¯¯¯1=2.3 mins. X2__ =2.6
Sample Standard Deviation of each Sample s1= 1.1 mins s2=1.0 mins.
  1. Are the samples dependent or independent? answered
  2. State your Null/Alternative hypotheses? Answered
  3. What is the test-statistic? Answered
  4. What is the p-value? answered
  5. What are the critical values? answered
  6. Does the test-statistic lie in the rejection region? answered
  7. Interpret the Result?
  8. Does the result change for a different value of alpha? Explain?
**General Ed. Task**

1) The samples are independent.

2) Null and Alternative Hypotheses  
   \( H_0: \mu_1 = \mu_2 \)  
   \( H_1: \mu_1 < \mu_2 \)

3) Calculation of the t-statistic:  
   \[
   t = \frac{2.3 - 2.6}{\sqrt{\frac{(46-1) \times 1.2^2 + (50-1) \times 1.0^2}{46 + 50 - 2} \times \left(\frac{1}{46} + \frac{1}{50}\right)}} = -1.40
   \]

4) P-Value: 0.0824 (Left-tailed)

5) Critical Value: -1.6601

6) Since 0.0824 > 0.05, the null hypothesis is not rejected.
Transcribed Image Text:**General Ed. Task** 1) The samples are independent. 2) Null and Alternative Hypotheses \( H_0: \mu_1 = \mu_2 \) \( H_1: \mu_1 < \mu_2 \) 3) Calculation of the t-statistic: \[ t = \frac{2.3 - 2.6}{\sqrt{\frac{(46-1) \times 1.2^2 + (50-1) \times 1.0^2}{46 + 50 - 2} \times \left(\frac{1}{46} + \frac{1}{50}\right)}} = -1.40 \] 4) P-Value: 0.0824 (Left-tailed) 5) Critical Value: -1.6601 6) Since 0.0824 > 0.05, the null hypothesis is not rejected.
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