A sample of C₃H₄Br₂ has a normal boiling temperature of 131.5 °C. The enthalpy of vaporization for this compound is 35.4 kJ/mol. How much energy would be required to heat a 10.1 gram sample of liquid C₃H₄Br₂ from 97.5 °C to a gas at 187.2 °C? The specific heat for the liquid is 0.865 J/g・°C and the specific heat for the gas is 0.364 J/g・°C.

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A sample of C₃H₄Br₂ has a normal boiling temperature of 131.5 °C. The enthalpy of vaporization for this compound is 35.4 kJ/mol. How much energy would be required to heat a 10.1 gram sample of liquid C₃H₄Br₂ from 97.5 °C to a gas at 187.2 °C? The specific heat for the liquid is 0.865 J/g・°C and the specific heat for the gas is 0.364 J/g・°C.

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The heat required to change the temperature form T1= 97.5 °C                                         T2= 131.5 °CFor liquid specific heat 0.684 J/g°C    Q1=mCT     =10.1 g×0.684×131.5-97.5       =6.9084×34 Q1=234.88J.......1stNow heat required to change the state of C3H4Br2 liquid to gas Q2=mHvap    =10.1×35400200    =1787.7JNow the heat required to change the temperature form  131.5 °C to 187.2 °CFor gas specific heat C=0.364 J/g°CQ3=mCT     =10.1 g× 0.364 J/g°C×187.2-131.5     =10.1 g× 0.364 J/g°C×55.7     =204.77J   .                     

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