A sample of Br, (g) takes 38.0 min to effuse through a membrane. How long would it take the same number of moles of Ar(g) to effuse through the same membrane? time: min
A sample of Br, (g) takes 38.0 min to effuse through a membrane. How long would it take the same number of moles of Ar(g) to effuse through the same membrane? time: min
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
A sample of Br₂(g) takes 38.0 min to effuse through a membrane. How long would it take the same number of moles of Ar(g) to effuse through the same membrane?
**Input Box:**
- Time: [________] min
**Explanation:**
This problem involves calculating the effusion time of a gas through a membrane, applying Graham's Law of Effusion. According to Graham's Law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The formula to relate the effusion rates of two gases is:
\[
\frac{\text{Rate of effusion of Gas 1}}{\text{Rate of effusion of Gas 2}} = \sqrt{\frac{\text{Molar mass of Gas 2}}{\text{Molar mass of Gas 1}}}
\]
In this case, we need to find the effusion time for Ar(g) given the effusion time for Br₂(g), considering their respective molar masses.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0313a3d2-f852-4af8-9bdc-dcc8f1b4e305%2Fea531e0e-3300-424e-bcb1-cdc3a0ef0ace%2Flhzq1v7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A sample of Br₂(g) takes 38.0 min to effuse through a membrane. How long would it take the same number of moles of Ar(g) to effuse through the same membrane?
**Input Box:**
- Time: [________] min
**Explanation:**
This problem involves calculating the effusion time of a gas through a membrane, applying Graham's Law of Effusion. According to Graham's Law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. The formula to relate the effusion rates of two gases is:
\[
\frac{\text{Rate of effusion of Gas 1}}{\text{Rate of effusion of Gas 2}} = \sqrt{\frac{\text{Molar mass of Gas 2}}{\text{Molar mass of Gas 1}}}
\]
In this case, we need to find the effusion time for Ar(g) given the effusion time for Br₂(g), considering their respective molar masses.
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