A sample of birth weights of 16 girls was taken. Below are the results (in g): 3236.4 2155 3154.9 4485.4 4547.1 3916.9 3687.1 3808.1 2599.1 3183.7 2826 2392.3 2758.5 2914.3 3438.9 3051.7 ¯x=x¯= 3259.7 g s=s= 689.71 g Use a 10% significance level to test the claim that the standard deviation of birth weights of girls is greater than the standard deviation of birth weights of boys, which is 550 g. Round all answers to 3 decimal places if possible. Procedure: Select an answer One proportion Z Hypothesis Test One mean Z Hypothesis Test One variance χ² Hypothesis Test One mean T Hypothesis Test Step 1. Hypotheses Set-Up: H0:H0: Select an answer p μ σ² = Ha:Ha: Select an answer p μ σ² ? ≠ > < The test is a Select an answer left-tailed two-tailed right-tailed test. Step 2. The significance level is α=α= Step 3. Compute the value of the test statistic: Select an answer χ₀² z₀ t₀ = Step 4. Testing Procedure: Provide the critical value(s) for the Rejection Region. For a one-tailed test, use DNE for the unneeded critical value. Left CV = Right CV = The p-value is . LinkOpens externally to Chi-Square Table: https://www.itl.nist.gov/div898/handbook/eda/section3/eda3674.htmOpens externally Step 5. Decision Is the test statistic in the rejection region? ? yes no Is the p-value less than the significance level? ? yes no Conclusion: Select an answer Reject the null hypothesis in favor of the alternative. Do not reject the null hypothesis in favor of the alternative. Step 6. Interpretation: At a 10% significance level we Select an answer do not do have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
A sample of birth weights of 16 girls was taken. Below are the results (in g):
3236.4 | 2155 | 3154.9 | 4485.4 | 4547.1 |
3916.9 | 3687.1 | 3808.1 | 2599.1 | 3183.7 |
2826 | 2392.3 | 2758.5 | 2914.3 | 3438.9 |
3051.7 |
¯x=x¯= 3259.7 g
s=s= 689.71 g
Use a 10% significance level to test the claim that the standard deviation of birth weights of girls is greater than the standard deviation of birth weights of boys, which is 550 g.
Round all answers to 3 decimal places if possible.
Procedure: Select an answer One proportion Z Hypothesis Test One mean Z Hypothesis Test One variance χ² Hypothesis Test One mean T Hypothesis Test
Step 1. Hypotheses Set-Up:
H0:H0: Select an answer p μ σ² =
Ha:Ha: Select an answer p μ σ² ? ≠ > <
The test is a Select an answer left-tailed two-tailed right-tailed test.
Step 2. The significance level is α=α=
Step 3. Compute the value of the test statistic: Select an answer χ₀² z₀ t₀ =
Step 4. Testing Procedure:
Provide the critical value(s) for the Rejection Region. For a one-tailed test, use DNE for the unneeded critical value.
- Left CV =
- Right CV =
The p-value is .
LinkOpens externally to Chi-Square Table: https://www.itl.nist.gov/div898/handbook/eda/section3/eda3674.htmOpens externally
Step 5. Decision
Is the test statistic in the rejection region? ? yes no
Is the p-value less than the significance level? ? yes no
Conclusion: Select an answer Reject the null hypothesis in favor of the alternative. Do not reject the null hypothesis in favor of the alternative.
Step 6. Interpretation:
At a 10% significance level we Select an answer do not do have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
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