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A sample of 8 measurements, randomly selected from a normally distributed population, resulted in a sample mean, = 9.3 and sample standard deviation s = 1.88. Using a = 0.01, test the null hypothesis that the mean of the population is 7.6 against the alternative hypothesis that the mean of the population, μ< 7.6 by giving the following: (a) the degree of freedom (b) the critical t value (c) the test statistic

A sample of 8 measurements, randomly selected from a normally distributed population, resulted in a sample mean, = 9.3 and sample standard deviation s = 1.88. Using a = 0.01, test the null hypothesis that the mean of the population is 7.6 against the alternative hypothesis that the mean of the population, μ< 7.6 by giving the following: (a) the degree of freedom (b) the critical t value (c) the test statistic

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A sample of 8 measurements, randomly selected from a normally distributed population, resulted in a sample mean, \( \bar{x} = 9.3 \) and sample standard deviation \( s = 1.88 \). Using \( \alpha = 0.01 \), test the null hypothesis that the mean of the population is 7.6 against the alternative hypothesis that the mean of the population, \( \mu < 7.6 \) by giving the following: (a) the degree of freedom [ ] (b) the critical \( t \) value [ ] (c) the test statistic [ ]
Transcribed Image Text:A sample of 8 measurements, randomly selected from a normally distributed population, resulted in a sample mean, \( \bar{x} = 9.3 \) and sample standard deviation \( s = 1.88 \). Using \( \alpha = 0.01 \), test the null hypothesis that the mean of the population is 7.6 against the alternative hypothesis that the mean of the population, \( \mu < 7.6 \) by giving the following: (a) the degree of freedom [ ] (b) the critical \( t \) value [ ] (c) the test statistic [ ]
Expert Solution
Step 1: Given that

Sample size n=8

Sample mean=9.3

Standard deviation=1.88

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