A sample of 18 observations taken from a normally distributed population produced the following data: 28.2 27.1 25.5 25.2 31.5 23.3 26.1 24.4 28.5 37.4 23.9 28.6 27.8 25.5 27.5 25.1 22.5 22.7 Round your answers to three decimal places. a. What is the point estimate of u? I = 26.711 b. Make a 98% confidence interval for u. (| 24.559 28.862 c. What is the margin of error of estimate for u in part b? E =
A sample of 18 observations taken from a normally distributed population produced the following data: 28.2 27.1 25.5 25.2 31.5 23.3 26.1 24.4 28.5 37.4 23.9 28.6 27.8 25.5 27.5 25.1 22.5 22.7 Round your answers to three decimal places. a. What is the point estimate of u? I = 26.711 b. Make a 98% confidence interval for u. (| 24.559 28.862 c. What is the margin of error of estimate for u in part b? E =
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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For this question i have half of it done. I need help on how to find the margin of error of estimate for m in part b please
Transcribed Image Text:**Statistical Analysis of a Sample of Observations**
A sample of 18 observations taken from a normally distributed population produced the following data:
28.2, 27.1, 25.5, 25.2, 31.5, 23.3, 26.1, 24.4, 28.5, 37.4, 23.9, 28.6, 27.8, 25.5, 27.5, 25.1, 22.5, 22.7
### Analysis
- **Point Estimate of \(\mu\):**
- The sample mean (\(\bar{x}\)) serves as the point estimate for the population mean \(\mu\).
- \(\bar{x} = 26.711\)
- **98% Confidence Interval for \(\mu\):**
- A confidence interval is a range of values used to estimate the true population parameter.
- 98% Confidence Interval: (24.559, 28.862)
- **Margin of Error for Estimate of \(\mu\) in Part b:**
- The margin of error represents the maximum expected difference between the true population parameter and the sample estimate.
- \(E = \) *(value not provided in the image)*
Please ensure all numerical computations are verified for accuracy when applying statistical methods.
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