A sample of 1300 computer chips revealed that 43% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that more than 40% do not fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.10 level to support the company's claim? State the null and alternative hypotheses for the above scenario.
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A: The known values are, The null and alternative hypothesis is, Level of significance, The value of…
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- A large programming "bootcamp" claims that 90% of students who complete the bootcamp find employment within one month of graduation. An independent watchdog organization decides to evaluate this claim. They take a simple random sample of 100 students who have completed the bootcamp in the last five years. Of these, 78 say they found employment within one month of graduation. (a) What are the null and alternative hypotheses in terms of the original problem? Null hypothesis: Alternative hypothesis: (b) Write down what the box model looks like if the null hypothesis is true. (c) Calculate the z test statistic based on the information given. (Note: You may use either the sample percentage or the sum of draws as your test statistic. You should get the same answer either way.) Z = (d) Now calculate the p-value. p = (e) What should the organization conclude based on this test? Specifically, is there enough evidence to reject the company's claim? YES or NOTyped plz and asap thanks Please I want quality solution please"At a certain college, it is estimated that about 65% of the students have cars on campus, and with this number, the parking lot is fully occupied. Would you suggest to increase the parking lot space if, in a random sample of 61 college students, 44 are found to have cars? Use 0.01 level of significance." A There is sufficent evidence to say that there is a need to increase the parking lot space. No sufficient data to make a conclusion. "Certainly, the parking lot is enough." It is safe to assume that the parking lot is enough
- A decade-old study found that the proportion of high school seniors who felt that getting rich" was an important personal goal was 66%. Suppose that we have reason to believe that this proportion has changed, and we wish to carry out a hypothesis test to see if our belief can be supported. State the null hypothesis H. and the alternative hypothesis H, that we would use for this test. Ho: H OSO Submit Assignmen Privacy Accessibili Continue O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use reviousA textbook publisher claims that 84% of college students enrolled in a course that uses their textbooks pass the class. One professor thinks the proportion is actually higher. He surveys 177 students in classes that use a textbook from the textbook publisher and finds the 153 of those students ultimately pass the class. Perform a hypothesis test using a 4% level of significance. Step 1: State the null and alternative hypotheses. Ho: pvv .84 Ha: .84 (So we will be performing a right-tailed Vv test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are normally distributed ♥▼ with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. = P(zv %3D P(p'v2v p-value = Step 4: Make a Conclusion About the null hypothesis. = a, we do not reject the null Since the p-value = hypothesis. O We cannot…A newsletter publisher believes that more than 79% of their readers own a personal computer. Is there sufficient evidence at the 0.02 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.
- According to the Centers of Disease Control, about 22% of American young people between the ages of 12 and 19 are obese.A student claims that the students in his local schools are in better shape than the national average, so their proportion of obese students is less than 22%. Which are the appropriate null and alternative hypotheses for this study? H0: p = 22%, HA: p < 22% H0: p ≠ 0, HA: p = 0 H0: p = 22%, HA: p > 22% H0: p = 22%, HA: p ≠ 22% Suppose that the result is to Fail to reject H0.Which is the proper conclusion? There is sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students. There is not enough information to answer this question. There is not sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students.One particular professional association of investors conducts a weekly survey of its members to measure the percent who are bullish, bearish, and neutral on the stock market for the next six months. The survey results showed 38.1% bullish, 22.8% neutral, and 39.1% bearish. Assume these results are based on a sample of 300 members. (a) Over the long term, the proportion of bullish members is 0.39. Conduct a hypothesis test at the 5% level of significance to see if the current sample results show that bullish sentiment differs from its long term average of 0.39. What are your findings? Formulate the hypotheses that can be used to determine whether the bullish sentiment differs from its long term average of 0.39. Ho: P > 0.39 H: p ≤ 0.39 O Ho: P = 0.39 Ha: p = 0.39 Ho: p≥ 0.39 H₂: P 0.39 Ho: P < 0.39 Ha: p≥ 0.39 Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion?…Takeout Food A magazine article reported that 14% of adults buy takeout food every day. A fast-food restaurant owner surveyed 180 customers and found that 31 said that they purchased takeout food every day. At a=0.01, is there evidence to believe the article's claim? Use the critical value method with tables. Part 1 of 5 (a) State the hypotheses and identify the claim. This hy is a two-tailed V test. Part (b th e critical vaiue, separate them with co Critic Part: 2 / 5 Part 3 of 5 (c) Compute the test value. Always round z score values to at least two decimal places. z=
- Among a simple random sample of 325 American adults who do not have a four-year college degree and are not currently enrolled in school, 45% said they decided not to go to college because they could not afford school. (a) A newspaper article states that only a minority of the Americans who decide not to go to college do so because they cannot afford it and uses the point estimate from this survey as evidence. Conduct a hypothesis test to determine if these data provide strong evidence supporting this statement. Use a significance level of a = 0.04. Но : prop HA: prop < p-value: Based on this information, we may Reject the Null Hypothesis (b) Calculate a 99% confidence interval for the proportion of Americans who decided not to go to college because they could not afford school.A large programming “bootcamp” claims that 90% of students who complete the bootcamp find employment within one month of graduation. An independent watchdog organization decides to evaluate this claim. They take a simple random sample of 100 students who have completed the bootcamp in the last five years. Of these, 78 say they found employment within one month of graduation.(a) What are the null and alternative hypotheses in terms of the original problem? Null hypothesis: Alternative hypothesis: (b) Write down what the box model looks like if the null hypothesis is true. (c) Calculate the z test statistic based on the information given. (Note: You may use either the sample percentage or the sum of draws as your test statistic. You should get the same answer either way.) z = _______ (d) Now calculate the p-value. p = _______ (e) What should the organization conclude based on this test? Specifically, is there enough evidence to reject the company’s claim? YES…