A sample contained a mixture of MgCO 3 and SrCO 3. The amount of MgCO 3 was determined by reacting 6.488 g of the sample with an excess of HCl to release CO 2 from each compound; MgCO 3(s) + 2 HCl(aq) → MgCl 2 + CO 2(g) SrCO 3(s) + 2 HCl(aq) → SrCl 2 + CO 2(g) If the sample reacted completely and produced 1549 mL of carbon dioxide at 25.28 °C and 709.8 mm Hg, what was the mass percentage of MgCO 3 in the mixture?

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QUESTION 7

  1. A sample contained a mixture of MgCO 3 and SrCO 3. The amount of MgCO 3 was determined by reacting 6.488 g of the sample with an excess of HCl to release CO 2 from each compound;

    MgCO 3(s) + 2 HCl(aq) → MgCl 2 + CO 2(g)
    SrCO 3(s) + 2 HCl(aq) → SrCl 2 + CO 2(g)


    If the sample reacted completely and produced 1549 mL of carbon dioxide at 25.28 °C and 709.8 mm Hg, what was the mass percentage of MgCO 3 in the mixture?

    Key Concept:Stoichiometric reactions with gases.
    StrategyThis is a regular stoichiometry problem involving gases. P, V and T → n(gas) total = sum of mole of the two compounds.→mol of each compound = m/FM; sum of masses of each = total mass. Use this information to solve for the mass of each compound.

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