A sample consists of the following n = 6 scores: 5, 5, 5, 8, 8, 8 Transform the distribution so that it has a new mean of M = 100 and standard deviation of s = 20. What is the new, transformed score for the original score of X = 5? new X =

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### Statistical Transformation Example

#### Sample Data:
A sample consists of the following \( n = 6 \) scores: 
\[ 5, 5, 5, 8, 8, 8 \]

#### Task:
Transform the distribution so that it has a new mean of \( M = 100 \) and a standard deviation of \( s = 20 \).

#### Question:
What is the new, transformed score for the original score of \( X = 5 \)?

**New \( X \) = [__________]**

---

### How to Transform the Scores
To transform the scores to a new distribution with a specified mean (M) and standard deviation (s), you can use the following steps:

1. Calculate the original mean (\( \bar{X} \)) and standard deviation (\( s_X \)) of the sample.
2. Use the formula for transforming each score: 

\[ \text{New } X = M + \left( \frac{X - \bar{X}}{s_X} \right) \times s \]

Where:
- \( X \) is the original score.
- \( \bar{X} \) is the original mean.
- \( s_X \) is the original standard deviation.
- \( M \) is the new mean.
- \( s \) is the new standard deviation.

### Example Calculation:
1. **Calculate the original mean (\( \bar{X} \)):**

\[ \bar{X} = \frac{\sum_{i=1}^{n} X_i}{n} = \frac{5 + 5 + 5 + 8 + 8 + 8}{6} = 6.5 \]

2. **Calculate the original standard deviation (\( s_X \)):**

\[ s_X = \sqrt{\frac{\sum (X_i - \bar{X})^2}{n}} = \sqrt{\frac{(5 - 6.5)^2 + (5 - 6.5)^2 + (5 - 6.5)^2 + (8 - 6.5)^2 + (8 - 6.5)^2 + (8 - 6.5)^2 }{6}} = 1.5 \]

3. **Transform the original score \( X = 5 \) using the new parameters \( M = 100 \) and \( s =
Transcribed Image Text:### Statistical Transformation Example #### Sample Data: A sample consists of the following \( n = 6 \) scores: \[ 5, 5, 5, 8, 8, 8 \] #### Task: Transform the distribution so that it has a new mean of \( M = 100 \) and a standard deviation of \( s = 20 \). #### Question: What is the new, transformed score for the original score of \( X = 5 \)? **New \( X \) = [__________]** --- ### How to Transform the Scores To transform the scores to a new distribution with a specified mean (M) and standard deviation (s), you can use the following steps: 1. Calculate the original mean (\( \bar{X} \)) and standard deviation (\( s_X \)) of the sample. 2. Use the formula for transforming each score: \[ \text{New } X = M + \left( \frac{X - \bar{X}}{s_X} \right) \times s \] Where: - \( X \) is the original score. - \( \bar{X} \) is the original mean. - \( s_X \) is the original standard deviation. - \( M \) is the new mean. - \( s \) is the new standard deviation. ### Example Calculation: 1. **Calculate the original mean (\( \bar{X} \)):** \[ \bar{X} = \frac{\sum_{i=1}^{n} X_i}{n} = \frac{5 + 5 + 5 + 8 + 8 + 8}{6} = 6.5 \] 2. **Calculate the original standard deviation (\( s_X \)):** \[ s_X = \sqrt{\frac{\sum (X_i - \bar{X})^2}{n}} = \sqrt{\frac{(5 - 6.5)^2 + (5 - 6.5)^2 + (5 - 6.5)^2 + (8 - 6.5)^2 + (8 - 6.5)^2 + (8 - 6.5)^2 }{6}} = 1.5 \] 3. **Transform the original score \( X = 5 \) using the new parameters \( M = 100 \) and \( s =
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