When engaging in weight-control (fitness/fat burning) types of exercise, a person is expected to attain approximately 60% of hisor her maximum heart rate. For 20-year-olds, this rate is approximately 120 bpm. A simple random sample of one hundred20-year-olds was taken, and the sample mean was found to be 107 bpm, with a standard deviation of 45 bpm. Researcherswonder if this is evidence to conclude that the expected level is actually lower than 120 bpm. To determine this, we test thefollowing hypotheses:Ho: H= 120 versus H₂ μ< 120Suppose the mean and standard deviation obtained were based on a sample of size 25 rather than 100. How would the P-value change?The P-value would remain unchanged because the variability measured by the standard deviation stays the same.The P-value would remain unchanged because the difference between x and the hypothesized value μ = 120 isunchanged.The P-value would be larger when using the smaller sample size.The P-value would be smaller when using the smaller sample size.

Hypothesis is an assumption that is being tested.

Answered: How would the P-value change? The…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The results of a common standardized test used in psychology research is designed so that the population mean is 175 and the standard deviation is 10. A subject earns a score of 183. What is the z-score for this raw score?
I'm started doing these, but I'm not sure if they are set up right. I am confused about the difference between a true variance and a sample standard deviation.
True or False. The standard deviation of the mean is less than the sample standard deviation because it estimates the variation of averages, which are more precise than single observations.
Is when the population standard deviation and variance are unknown. Justin wants to know whether a commonly prescribed drug does improvethe attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx, so he calculated s2x =1.96. (1) Create your own example of a Related/Paired Samples t-Test. You don't have to solve this example, but I want you to demonstrate that you understand the methodology (the way a study is designed) of the Paired-Samples t-Test. Include the following: IV: DV: Null Hypothesis: Alternative Hypothesis: I want you to show me that you know how to solve and interpret the results from a Paired - Samples t-Test. 2. A researcher studies the effect of cognitive psychotherapy on positive self-regard. The number of positive statements…
For her test grades, Gena has a mean = 65 and standard deviation = 25. Patti has a mean = 65 and standard deviation = 5. For which of the students can you more accurately predict the next test score, and why? Consider the variability of scores. Who is more likely to do either extremely well or extremely poorly on the next exam, and why? Explain the reason for adjusting the formula of the standard deviation/variance with n - 1 in the denominator?
It is widely claimed that a histogram is skewed to the left when the median is greater than the mean and to the right when the median is less than the mean. But there are exceptions to this claim. Demonstrate this exception by creating a data set that has at least 15 samples and plot the histogram.
IQ scores are normally distributed with a mean of 100 and a variance of 225. What percentage of people score between 130 and 145?
Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly is 120 millimeters of mercury (mm Hg), but she believes that the actual value is higher. She bases her belief on a recently reported study of 19 randomly selected, elderly adults. The sample mean systolic blood pressure of the adults in the study was 121 mm Hg , and the sample standard deviation was 20 mm Hg. Assume that the population of systolic blood pressures of elderly adults is normally distributed. Based on the study, at the 0.1 level of significance, can it be concluded that μ , the mean systolic blood pressure among elderly adults, is greater than 120 mm Hg? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (a) State the null hypothesis H0? and the alternative hypothesis H1? . H0:? H1:? (b) Determine the type of test statistic to…
What is the equation for The standard deviation of the distribution of sample means
Pyramid Lake is on the Paiute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a friend tells you that the average length of trout caught in Pyramid Lake isμ=19 inches. However, a survey reported that of a simple random sample of 38 fish caught, the mean length was 19.9 inches, with estimated standard deviation of 3.1 inches. Do these data indicate that the average length of a trout caught in Pyramid Lake is different from μ=19inches? Use α=0.001. What is the value of the test statistic? (Round your answer to two decimal places.)Find the P-value. (Round your answer to four decimal places.)
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The mean concentration for both suppliers is the same, but you suspect that the variability in concentration may differ for the two companies. The standard deviation of concentration in a random sample of n₁ = 10 batches produced by company 1 is s₁ = 4.7 grams per liter, and for company 2, a random sample of n₂ = 16 batches yield s₂ = 5.8 grams per liter. Is there sufficient evidence to conclude that the two populations variances differ? Use a = 0.05. a. Because 0.321 < 0.657 <3.77, fail to reject the null hypothesis b. Because 0.265 < 0.657 <3.12, fail to reject the null hypothesis c. Because 0.386 < 0.657 <3.01, fail to reject the null hypothesis d. None among the choices
The distribution of sample means for bi-monthly employee income at a particular company for samples of 70 employees is normal with a mean of $5921 and a standard deviation of $219. You take a random sample of 70 employees from the company and find that their mean bi-monthly income is $5668. How many standard deviations is the sample mean from the mean of the distribution of sample means?

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