A rubber pad for a machine mounting is to carry a load of 5 kN and to compress 5 mm under this load. If the stress in the rubber is not to exceed 280 kN/m², determine the diameter and thickness of a pad of circular cross-section. Take E for rubber as 1 MN/m?. Question 15

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ACT2.1_SEF024 Q15-22
Question 15 See p.275 Hannah and Hillier
A rubber pad for a machine mounting is to carry a load of 5 kN and to compress
5 mm under this load. If the stress in the rubber is not to exceed 280 kN/m², determine the
diameter and thickness of a pad of circular cross-section. Take E for rubber as 1 MN/m².
Question 15
(diameter = 150.78 mm,
thickness = 18mm)
%3D
Question 16 See p.276 Hannah and Hillier
Question 16 shows a steel strut with two grooves cut out along part of its length. Calculate
the total compression of the strut due to a load of 240 kN. E = 200 GN/m².
240 kN
20 mm
240 mm
10 mm
40 mm
360 mm
10 mm
40 mm
(X1 (solid 360 mm
length) = 0.27 mm;
X2 (grooved 240 mm
length) = 0.24 mm;
Total compression
%3D
%3D
(X1 + X2) = 0.51 mm)
%3D
Transcribed Image Text:ACT2.1_SEF024 Q15-22 Question 15 See p.275 Hannah and Hillier A rubber pad for a machine mounting is to carry a load of 5 kN and to compress 5 mm under this load. If the stress in the rubber is not to exceed 280 kN/m², determine the diameter and thickness of a pad of circular cross-section. Take E for rubber as 1 MN/m². Question 15 (diameter = 150.78 mm, thickness = 18mm) %3D Question 16 See p.276 Hannah and Hillier Question 16 shows a steel strut with two grooves cut out along part of its length. Calculate the total compression of the strut due to a load of 240 kN. E = 200 GN/m². 240 kN 20 mm 240 mm 10 mm 40 mm 360 mm 10 mm 40 mm (X1 (solid 360 mm length) = 0.27 mm; X2 (grooved 240 mm length) = 0.24 mm; Total compression %3D %3D (X1 + X2) = 0.51 mm) %3D
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