Answered: A rubber ball is attached to a string… | bartleby

Related questions

Question

A rubber ball is attached to a string and whirled around in a circle. If the string is 1.5 m long
(measured from the center of the ball to the far end of the string) and the ball's speed is 12
m/s, what is the ball's centripetal acceleration? The mass of the ball is 0.2 kg. What force is
acting on this ball as it is whirled in a circle?
Edit View Insert Format Tools Table

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

The International Space Station orbits the Earth in a circle with a radius of approximately 6688185 m (which is only a few hundred miles above Earth's surface). At that distance, the acceleration due to gravity is only 8.87m / (s ^ 2) what is the velocity of the space station in this orbit? Your answer should be in units of m / s
What is the magnitude of the Earth's centripetal acceleration? Given: Acceleration due gravity (earth surface) g = 9.8 m/s2= 9.8 N/kg Gravitational constant G = 6.67×10−11N·m2/kg2 Mass of the Sun 2.00×1030kg Mass of the Earth 5.97×1024kg Radius of the Earth 6.37×106m Radius of Earth’s Orbit 1.50×1011m Velocity: 29.870 m/s
A 615 kg car completes one lap in a time of 14.3 sec around a circular track with a radius of 50.0 m. What is the acceleration of the car? What force must the track exert on the car to produce this acceleration?
A 5 kg mass is spun around in a circle of radius 2m with a period of 7 s. What equation would you use to calculate the centripetal acceleration? Calculate the centripetal acceleration. Possible Formulas that can be used to answer the question: v=(2πr)/T ac=v2/r ac=(4π2r)/T2 Fc=mac Fg=mg F=(Gm1m2)/d2 g=Gm/r2 T2=(4π2/Gm)r3 v=√(Gm)/r g=9.80m/s2 G=6.67x10-11 (N∙m2)/kg2
A communications satellite orbits around Earth. Earth has a radius of 6380 km, and the satellite orbits 1140 km above Earth's surface. The satellite has a mass of 915 kg, and moves with a velocity of 7280 m/s. Based on this information, what is the centripetal force exerted on the satellite? 6450 N 89,900 N 14,700 N 8710 N
An athlete whirls a 7.00 kg hammer tied to the end of a 1.3 meter chain in a horizontal circle. The hammer makes one revolution in 1.0 seconds, what is the centripetal acceleration of the hammer? What is the tension in the chain?
A 5 kg mass is spun around in a circle of radius 2m with a period of 7 s. What equation would you use to find the centripetal force acting on the mass? Calculate the centripetal force acting on the mass. Possible Formulas that can be used to answer the question: v=(2πr)/T ac=v2/r ac=(4π2r)/T2 Fc=mac Fg=mg F=(Gm1m2)/d2 g=Gm/r2 T2=(4π2/Gm)r3 v=√(Gm)/r g=9.80m/s2 G=6.67x10-11 (N∙m2)/kg2
A car with a mass of 1380 kg is moving around a curve with a radius of 21.0 m at a constant speed of 15 m/s. What is the magnitude of the centripetal force?
1. Given the vectors M = -10āx + 4ã, – 8ả, and Ñ = 8å, + 7ã, – 2ã,, find: a. A unit vector in the direction of -M + 2Ñ b. The magnitude of 5å, + N – 3M c. M||2Ñ|(M + N)
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 4.33 m radius, if the riders is subjected to a centripetal acceleration 3.5 times that due to gravity, what is the spinning speed in unit of revolutions per minute? Use g = 9.8 m
Jupiter’s volcanic moon Io (it’s the most volcanic thing in our solar system!) completes a roughly circular orbit around the planet once every 42 hours. If the distance between Io and Jupiter is 4.22 × 108 m, what is thecentripetal acceleration of the moon?