(a) r(t) = ln ti + (t² + 3t)j + 4√tk; (0,4,4) 1 1 b) r(t) = (727); (1,1,1) t' t2,

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Find the tangential and normal components of the acceleration vector at the given point.
(a) r(t) = ln ti + (t² + 3t)j + 4√tk; (0,4,4)
1
1
1
(b) r(t) =
(7/7/7/7/7); (1,1,1)
t' t3
Transcribed Image Text:Find the tangential and normal components of the acceleration vector at the given point. (a) r(t) = ln ti + (t² + 3t)j + 4√tk; (0,4,4) 1 1 1 (b) r(t) = (7/7/7/7/7); (1,1,1) t' t3
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