A = Roll 16 kN/m' 6 m 4 6m + M = 96 kNm 4 m B = Pin

Q: what is the formula used in the -δp + δt = -δp + δt = -δp + δt part at the top? what is the…

A: Given:  (-δp + δt)A = (-δp + δt)B = (-δp + δt)C Required: To explain the  δp and δt meaning in the…

Q: A rectangular tube has an outside width of 100 mm, an outside depth of 150 mm, and a wall thickness…

A: σ=MyII=BH312-bh312=100×150312-80×130312=13478333.33mm4M=1.4k-m

Q: Question 2: For the Aluminium shaft shown in Figure 2 with "Shear Modulus (G) = 27 GPa", determine…

A:

Q: 1. A solid shaft ABCD of diameter d is fixed at A and subjected to torques applied at equally spaced…

A: Since, we answer only three sub-parts at a time so we will answer the first three sub-parts. Please…

Q: 50mm a biaxial load that results in B C Given: A “happy-little-cube" of material is subject O = 150…

A:

Q: 1. A steel rod is positioned vertically as shown in the figure. It is fixed at one end and…

A:

Q: In the figure below, a solid shaft with a diameter of 50 mm is subjected to the torques applied to…

A:

Q: The piston rod of diameter 20 mm and length 700 mm in hydraulic cylinder is subjected to compressive…

A: A piston rod- Diameter d=20 mm, Length L=700 mm, Compressive force P =10 kN, End conditions- Guided…

Q: The solid shaft is fixed to the support at C and subjected to the torsional loadings shown in the…

A:

Q: Calculating the maximum torsional stress and deflection angle in the shaft. (P2) Find the torsional…

A: Given Data: The diameter of a shaft is, D=0.015 m The radius of a groove is, r=0.00107 m The span of…

Q: Describe FIVE (5) basic assumptions upon the application of the Bernoulli equation. (a) A pitot tube…

A:

Q: Consider a solid circular shaft fixed at one end and free at the other end with a concentrated…

A:

Q: The sanding-drum mandrel shown in the figure is made for use with a hand drill. The mandrel is made…

A:

Q: A 30 mm diameter rod made of a ductile material with a yield strength of 200 MPa is subjected to…

A: Given : Diameter of rod = 30 mm Yield strength = 200 MPa  Bending moment = 150 N-m This is a problem…

Q: Taking 'k' components 0. 77TEC + 0. 8TBD=1440. -(1) Taking 'j' components 0. 514TEC – 1.6TBD=0.….…

A:

Q: When prospecting for land, mining companies use drills to extract ground samples from the ground.…

A:

Q: The motor shown in the figure produces a torque of 225 N·m in shaft (1).  If the shear stress in…

A:

Q: 2.41 The device shown consists of a disk that is rotated by a shaft. The disk is positioned very…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.