Answered: A rod has length 0.900 m and mass 0.600… | bartleby

Related questions

Question

A rod has length 0.900 m and mass 0.600 kg and is pivoted at
one end. The rod is not uniform; the center of mass of the rod is not at its
center but is 0.500 m from the pivot. The period of the rod’s motion as a pendulum
is 1.59 s. What is the moment of inertia of the rod around the pivot?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A 3.72 kg iron box is suspended from a spring with a spring constant of k=18 N/m. The mass is pulled 0.35 m downward from its equilibrium position and allowed to oscillate. a) what will the angular velocity be for this iron box? b) with what period will the iron box oscillate?
A thin rod of length L = 5 m and mass m has a linear density A(x) = Ax³ where x is the distance from the rod's left end. X(x) has units of kg/m and A = 6.38 with appropriate units that can't be displayed nicely due to Canvas limitations. Calculate the rod's moment of inertia I about an axis through x = 0 and perpendicular to the rod's length. (Hint: Evaluate the integral I = fr² dm where r = x is the distance from the axis to each element of mass dm = X(x) dx . Note: The rod's total mass mass m isn't needed but, if you would like to know it, you can find it by evaluating the integral m = f dm = f(x) dx.) I= kg m²
A uniform disk of radius 0.529 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.237 N applied at the rim causes an angular of 0.119 rads/s^2. Find the mass of the disk
In the figure, a 7.42 g bullet is fıred into a 0.531 kg block attached to the end of a 0.914 m nonuniform rod of mass 0.909 kg. The block- rod-bullet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.0305 kg-m?. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 3.51 rad/s, what is the bullet's speed just before impact?
A uniform thin rod of mass M = 3.37 kg pivots about an axis through its center and perpendicular to its length. Two small bodies, each of mass m = 0.219 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I = 0.975 kg-m? ? L = m M. m m L
A .20 kg mass is sitting on a frictionless 1 m long incline and is attached via cable to the inner axle (radius .20 m). An unknown mass is attached via another cable to the outer wheel (radius .40 m). The wheel/axle has moment of inertia .053 kg*m^2. Find the unknown mass balance the system reconsider the previous problem without the hanging mess. The system is released from rest when the mass is at the top of the incline. use an energy analysis to find the speed of mass at the bottom of the incline if the incline is 1 m long.
A thin rod of mass 0.800 kg and length 0.700 m has a fixed pivot at one end. The rod is held horizontally and released from rest. The rod swings downward and back up again like a pendulum. The rotational inertia of a thin rod rotating about one end is I=13ML2. Disregard friction and air resistance.(a) Determine the initial angular acceleration of the rod just as it is released.(b) Determine the maximum angular speed of the rod as it swings back and forth.
You have a hoop that is 10 cm in radius that you need to measure the mass of.You do not have a scale, but you do have a solid disk with a radius of 12 cm and a knownmass of 5 kg, and you have a device that will measure rotational speed. You set the disk on aplatform, give it a spin so that it is rotating clockwise at 30 rad/s, then set the hoop on thedisk. Afterwards, the system is rotating at 20 rad/s. What is the mass of the hoop? Thank you
The 184-kg spool has a radius of gyration about its mass center of kg = 300 mm. If the couple moment is applied to the spool and the coefficient of kinetic friction between the spool and the ground is μ = 0.2, determine the angular acceleration of the spool, the acceleration of G and the tension in the cable. ( Figure 1) Figure 0.4 m 0.6 m B M = 450 N.m 1 of 1 Determine the angular acceleration of the spool. Express your answer to three significant figures and include the appropriate units. α = Submit Part B aG= O Value X Incorrect; Try Again Submit Part C μÃ Determine the acceleration of G. Express your answer to three significant figures and include the appropriate units. O Previous Answers Request Answer O μA Value Units Request Answer ? μA Units Determine the tension in the cable. Express your answer to three significant figures and include the appropriate units. ? ?
A lump of putty (0.050 kg) hits a contraption that is made of a uniform solid cylinder rotating about its center of mass and two rods that are attached to the sides of the cylinder. The moment of inertia of the contraption is 0.250 kg∙m2. After the collision, the putty attaches to the contraption 0.15 m from the axis of rotation and the combination is rotating at 1.0 rad/s. Determine the linear speed of the putty before the collision. Determine the angular impulse on the putty and on the block separately to show that they follow Newton’s 3rd law. How much energy is lost in the collision? Where did it go?
A small ball of mass 0.90 kg is attached to one end of a 1.20-m-long massless rod, and the other end of the rod is hung from a pivot. When the resulting pendulum is 23° from the vertical, what is the magnitude of the torque about the pivot?
10.20 A string is wrapped Figure E10.20 several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. The free end of the string is held in place and the hoop is released from rest (Fig. E10.20). After the hoop has descended 75.0 cm, calculate (a) the angular speed of the rotating hoop and (b) the speed of its center. 0 0.0800 m

SEE MORE QUESTIONS