A rod has a diameter of 2 in. It is subjected to a torque of 12 kip*in. and a bending moment M. The greatest principal stress at the point of maximum bending stress is 15 ksi. Determine the magnitude of the bending moment. 12 kip-in. M

The tool shown is made up of an oak wood part. The tool works in torsion and the allowable shear stress for the wood is 213 psi. If the wooden handle has as a minimum section a circular area of diameter 1.4, find the maximum allowable torque T. Express the result in Ib-in with a decimal approximation T D T

If the allowable normal stress is 120MPa and the allowable shear stress is 60MPa, what is the resultant force at the support A?

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Question 1: A member having the dimensions shown is used to resist an internal bending moment of M kNm. Determine the maximum stress in the member if the moment is applied (a) about the z axis (as shown) (b) about the y axis. Sketch the stress distribution for each case. Take: M= 98 kNm mm A= 208 mm B= 158 mm B mm Solution: The moment of inertia of the cross-section about z and y axes are 1 AB³ 12 |(10-) m* 1 ВАЗ — 12 I, |(10) m* = For the bending about z axis, c = m Mc O pax MPа Iz For the bending about y axis, c = m Mc MPа Iy max z MPa KN=M Omax Y MPa. M KN-M MPa O max Z Omax Y MPa

Q3) The bar is subjected to a moment of M= 60 Nm. Determine the smallest radius rof the fillets so that an allowable bending stress of oalow 240 MPa is not exceeded. 80 mm 6 mm 16 mm M

Determine the ff: •Internal bending moment at point c •internal shear force at point c •internal normal force at point c Asap please.

Q1- Prove that the shear stress of circular shaft under pure torsion is Tr %3D Tmax Ip Ere

2. If the allowable shear stress for each of the steel pins at A and B is tpe 6.5 ksi and the allowable normal stress for bar CB is Operm 10 ksi, determine the diameter of the pins at A and B and that of the square bar CB. Pin A is in double shear while Pin B is in single shear. Ignore points D and E. (^ } 2.5 ft -3 ft -5 ft 150 lb/ft Fx =

Two solid steel shafts of different diameters are joined together at point C. The diameter of the smaller shaft is 0.5 inch, while the diameter of the larger shaft is 1 inch. If the supports at both ends, A & B, are unyielding / rigid, and a counterclockwise torque of 500 ft lb is applied at point D, determine the maximum shear stress in the shaft in ksi. The modulus of rigidity for steel is 10800 ksi. 8 in 5 in 12 in