A rock moving in the +x-direction with speed 16.0 m/s has a net force applied to it at time t = 0, and this produces a constant acceleration in the -x-direction that has magnitude 4.00 m/s2. For what three times t after the force is applied is the rock a distance of 24.0 m from its position at t = 0? For each of these three values of t, what is the velocity (magnitude and direction) of the rock?

A rock moving in the +x-direction with speed 16.0 m/s has a net force applied to it at time t = 0, and this produces a constant acceleration in the -x-direction that has magnitude 4.00 m/s2. For what three times t after the force is applied is the rock a distance of 24.0 m from its position at t = 0? For each of these three values of t, what is the velocity (magnitude and direction) of the rock?

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Question 15, Physics - equation sheet attached