A rock glides from a ramp which is 6m above the ground as shown in the figure below. If the horizontal velocity of the rock is 12 m/s, calculate the time required for the rock to reach the ground and the range R where rocks begin to pile up. A 12 m/s a = g 6 m
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- You have put a sonar device at the top of a frictionless inclined plane, as shown in the diagram below. That device allows you to measure the distance an object is from the device, as well as the speed and the acceleration of that object. If we decide that the origin (h = 0) is at the sonar device, we want to know what the height change is as we slide down the incline. 0 For an angle below the horizontal of 6.46, we see that our object has slid a distance 1.13 m, as measured along the incline itself. Calculate the height change in meters - and report your answer as a negative number. (This value would be useful for calculating the change in gravitational potential energy, as we will do in the lab.) h=o 10% O i 26 QUATU 99+ hp X 55 83°F 3:11 PM 10/16/2022 Ctrl 0A cannonball is shot from the edge of a 20-m-high vertical cliff with an initial speed of 50 m/s at an angle of 40° above the horizontal. Assume that the ground at the bottom of the cliff is flat and level. How long will the cannonball be in the air? (See the diagram below.) Assume that g = 9.8 m/s2 Vo 50 m/s Vo. 400 Cannonball 20 m а. 7.1 s O b.6.1 s Ос. 5.1 s d. 9.1 s е. 8.1 sA student fires a cannonball vertically upwards with a speed of 31.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. What was the cannonball's maximum height? unit How long did the cannonball rise? unit What was the cannonball's total flight time? unit
- Consider the following descriptions of the vertical motion of an object subject only to the acceleration due to gravity. Begin with the acceleration equation a(t) = v'(t) = g, where g= - 9.8 m/s. a. Find the velocity of the object for all relevant times. b. Find the position of the object for all relevant times. c. Find the time when the object reaches its highest point. What is the height? d. Find the time when the object strikes the ground. A softball is popped up vertically (from the ground) with a velocity of 25 m/s. а. v(t) b. s(t) = %3D c. The object's highest point is m at time t= S. (Simplify your answers. Round to two decimal places as needed.) d. t= (Simplify your answer. Round to two decimal places as needed.)M =500kg v16.40 m/s h,-100 m X-110m h. Fk = 250N V-43 m/s The figure depicts the notion of the car from point A to C. If the velocity (Vc)of the car is 16.40 m/s, find the height hc.