**Projectile Motion Problem**A cannonball is shot from the edge of a 20-meter-high vertical cliff with an initial speed of 50 m/s at an angle of 40° above the horizontal. Assume that the ground at the bottom of the cliff is flat and level. How long will the cannonball be in the air? Assume that \( g = 9.8 \, \text{m/s}^2 \).**Diagram Explanation:**The diagram illustrates the cannonball's trajectory from the cliff to the ground. Key features include:- **Initial Velocity (\( v_0 \))**: 50 m/s at a 40° angle above the horizontal.- **Vertical Drop**: The cliff is 20 meters high.- **Trajectory Path**: Depicted as a parabolic arc indicating the cannonball's motion due to gravity.- **Variable \( x \)**: Represents the horizontal distance traveled by the cannonball.**Options for Time in Air:**- a. 7.1 s- b. 6.1 s- c. 5.1 s- d. 9.1 s- e. 8.1 sConsider using the equations of motion for projectile motion to solve for the time the cannonball remains airborne.

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A cannonball is shot from the edge of a 20-m-high vertical cliff with an initial speed of 50 m/s at an angle of 400 above the horizontal. Assume that the ground at the bottom of the cliff is flat and level. How long will the cannonball be in the air? (See the diagram below.) Assume that g = 9.8 m/s- Vo = 50 m/s %3D Vo. 400 Cannonball 20 m

A cannonball is shot from the edge of a 20-m-high vertical cliff with an initial speed of 50 m/s at an angle of 400 above the horizontal. Assume that the ground at the bottom of the cliff is flat and level. How long will the cannonball be in the air? (See the diagram below.) Assume that g = 9.8 m/s- Vo = 50 m/s %3D Vo. 400 Cannonball 20 m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Projectile Motion Problem**

A cannonball is shot from the edge of a 20-meter-high vertical cliff with an initial speed of 50 m/s at an angle of 40° above the horizontal. Assume that the ground at the bottom of the cliff is flat and level. How long will the cannonball be in the air? Assume that \( g = 9.8 \, \text{m/s}^2 \).

**Diagram Explanation:**

The diagram illustrates the cannonball's trajectory from the cliff to the ground. Key features include:

- **Initial Velocity (\( v_0 \))**: 50 m/s at a 40° angle above the horizontal.
- **Vertical Drop**: The cliff is 20 meters high.
- **Trajectory Path**: Depicted as a parabolic arc indicating the cannonball's motion due to gravity.
- **Variable \( x \)**: Represents the horizontal distance traveled by the cannonball.

**Options for Time in Air:**

- a. 7.1 s
- b. 6.1 s
- c. 5.1 s
- d. 9.1 s
- e. 8.1 s

Consider using the equations of motion for projectile motion to solve for the time the cannonball remains airborne.

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