A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction? O A. 5-membered rhodacycle ring is formed O B. 6-membered rhodacycle ring is formed O C. the two units of C=C are reduced to alkane C-C bond. O D. the two units of C=C are inserted to the rhodium metal centre
A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction? O A. 5-membered rhodacycle ring is formed O B. 6-membered rhodacycle ring is formed O C. the two units of C=C are reduced to alkane C-C bond. O D. the two units of C=C are inserted to the rhodium metal centre
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction?
O A. 5-membered rhodacycle ring is formed
O B. 6-membered rhodacycle ring is formed
O C. the two units of C=C are reduced to alkane C-C bond.
O D. the two units of C=C are inserted to the rhodium metal centre](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b1fcfce-22dc-4873-916d-17b631bc48b4%2Fe0ee35fe-8035-495d-a32e-08344c8a9275%2Fcghdl3g_processed.png&w=3840&q=75)
Transcribed Image Text:A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction?
O A. 5-membered rhodacycle ring is formed
O B. 6-membered rhodacycle ring is formed
O C. the two units of C=C are reduced to alkane C-C bond.
O D. the two units of C=C are inserted to the rhodium metal centre
![Why can an organometallic complex perform the reactions such as insertion where normal coordination complex could not perform?
O A. Because of the intramolecular pi-electron charge transfer in the ligand.
OB.
Because of the intermolecular pi-electron charge transfer in the ligand.
Because the presence of dorbitals in the metal centre.
O D. Because of the metal to ligand pi-electron charge transfer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b1fcfce-22dc-4873-916d-17b631bc48b4%2Fe0ee35fe-8035-495d-a32e-08344c8a9275%2Fuijsw02_processed.png&w=3840&q=75)
Transcribed Image Text:Why can an organometallic complex perform the reactions such as insertion where normal coordination complex could not perform?
O A. Because of the intramolecular pi-electron charge transfer in the ligand.
OB.
Because of the intermolecular pi-electron charge transfer in the ligand.
Because the presence of dorbitals in the metal centre.
O D. Because of the metal to ligand pi-electron charge transfer.
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