a RF, RF2 Wtp Wt, ET; = 0 = (RF;)(1) = (Wt)(d)- (Wt,)('/2 ) %3D A 75 kg. 1.75 m tall person lays on a 3 kg. 2 m long board. The reaction force reading on the scale is 400 N. What is the torque due to the person?
a RF, RF2 Wtp Wt, ET; = 0 = (RF;)(1) = (Wt)(d)- (Wt,)('/2 ) %3D A 75 kg. 1.75 m tall person lays on a 3 kg. 2 m long board. The reaction force reading on the scale is 400 N. What is the torque due to the person?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![a
RF
RF2
Wt,
Wtb
ET; = 0 = (RF;)() = (Wt)(d)- (Wt,)('/2 1)
A 75 kg, 1.75 m tall person lays on a 3 kg. 2 m long board. The reaction force reading on the scale is 400 N. What is the torque
due to the person?
O-735.75 Nm
O -771.75 Nm
800 Nm
O 29 43 Nm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F828ce15e-5110-4547-95d6-c4d8b77d9cae%2F3854a6c2-0632-446c-9d6e-2d62ba8728e0%2F5fzbii_processed.png&w=3840&q=75)
Transcribed Image Text:a
RF
RF2
Wt,
Wtb
ET; = 0 = (RF;)() = (Wt)(d)- (Wt,)('/2 1)
A 75 kg, 1.75 m tall person lays on a 3 kg. 2 m long board. The reaction force reading on the scale is 400 N. What is the torque
due to the person?
O-735.75 Nm
O -771.75 Nm
800 Nm
O 29 43 Nm
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