A resistive force is applied to the same mechanical system above, and the amplitude of oscillations decreases 100 times after 1s from the start of oscillations. What is the dampin constant? By what factor does the amplitude change in one period of these damped oscillations?
A resistive force is applied to the same mechanical system above, and the amplitude of oscillations decreases 100 times after 1s from the start of oscillations. What is the dampin constant? By what factor does the amplitude change in one period of these damped oscillations?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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By what factor does the amplitude change in one period of these damped oscillations?
![A resistive force is applied to the same mechanical system above, and the amplitude of oscillations decreases 100 times after 1s from the start of oscillations. What is the damping constant? By what factor does the amplitude change in one period of these damped oscillations?
**Diagram**:
An illustration of a mechanical system is shown, with a mass \( M \) connected to a spring \( K \). This is labeled as "This is mechanical system above."
**Equations and Solution**:
1. The displacement in a damped oscillation system is given by:
\[
x(t) = Ae^{-\beta t} \cos(\omega t - \delta) \quad t = 0
\]
2. Examining the change in amplitude over time:
\[
\frac{A}{100} = A \cdot e^{-\beta t}
\]
3. Taking logarithms to solve for \(\beta\):
\[
\ln\left(\frac{1}{100}\right) = \ln\left(e^{-\beta t}\right)
\]
4. Simplifying the equation:
\[
+ \beta t = \frac{\ln\left(\frac{1}{100}\right)}{-t} \quad t = 1
\]
5. Solving for the damping constant \(\beta\):
\[
\beta = 4.605
\]
The damping constant \(\beta\) is found to be 4.605. This value determines how quickly the amplitude of the oscillations decreases.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc158a850-76a9-4504-97b9-8593e0926539%2Fa6c37024-fd8d-422c-b400-e1bac69bbc90%2Fdh0ndm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A resistive force is applied to the same mechanical system above, and the amplitude of oscillations decreases 100 times after 1s from the start of oscillations. What is the damping constant? By what factor does the amplitude change in one period of these damped oscillations?
**Diagram**:
An illustration of a mechanical system is shown, with a mass \( M \) connected to a spring \( K \). This is labeled as "This is mechanical system above."
**Equations and Solution**:
1. The displacement in a damped oscillation system is given by:
\[
x(t) = Ae^{-\beta t} \cos(\omega t - \delta) \quad t = 0
\]
2. Examining the change in amplitude over time:
\[
\frac{A}{100} = A \cdot e^{-\beta t}
\]
3. Taking logarithms to solve for \(\beta\):
\[
\ln\left(\frac{1}{100}\right) = \ln\left(e^{-\beta t}\right)
\]
4. Simplifying the equation:
\[
+ \beta t = \frac{\ln\left(\frac{1}{100}\right)}{-t} \quad t = 1
\]
5. Solving for the damping constant \(\beta\):
\[
\beta = 4.605
\]
The damping constant \(\beta\) is found to be 4.605. This value determines how quickly the amplitude of the oscillations decreases.
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