A researcher wanted to determine if carpeted or uncarpeted rooms contain more bacteria. The table shows the results for the number of bacteria per cubic foot for both types of rooms. A normal probability plot and boxplot indicate that the data are approximately normally distributed with no outliers. Do carpeted rooms have more bacteria than uncarpeted rooms at the a0.05 level of significance? Full data set O Uncarpeted Carpeted 8.1 13.8 11.7 13.1 13 6.1 8.7 9.5 14.1 8.9 14.4 10.2 13 9.4 E Click the icon to view the Student t-distribution table. What are the null and altemative hypotheses? Ho: carpetHno carpet Calculate the test statistic, to- to = (Round to two decimal places as needed.) Now find the critical value. Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) OA 6- OB. la/2- Do carpeted rooms have more bacteria than uncarpeted rooms at the a=0.05 level of significance? O A No, because the test statistic is in the critical region. O B. Yes, because the test statistic is in the critical region. O C. Yes, because the test statistic is not in the critical region. O D. No, because the test statistic is not in the critical region.
A researcher wanted to determine if carpeted or uncarpeted rooms contain more bacteria. The table shows the results for the number of bacteria per cubic foot for both types of rooms. A normal probability plot and boxplot indicate that the data are approximately normally distributed with no outliers. Do carpeted rooms have more bacteria than uncarpeted rooms at the a0.05 level of significance? Full data set O Uncarpeted Carpeted 8.1 13.8 11.7 13.1 13 6.1 8.7 9.5 14.1 8.9 14.4 10.2 13 9.4 E Click the icon to view the Student t-distribution table. What are the null and altemative hypotheses? Ho: carpetHno carpet Calculate the test statistic, to- to = (Round to two decimal places as needed.) Now find the critical value. Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) OA 6- OB. la/2- Do carpeted rooms have more bacteria than uncarpeted rooms at the a=0.05 level of significance? O A No, because the test statistic is in the critical region. O B. Yes, because the test statistic is in the critical region. O C. Yes, because the test statistic is not in the critical region. O D. No, because the test statistic is not in the critical region.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A researcher wanted to determine if carpeted or uncarpeted rooms contain more bacteria. The table shows the results for the number of bacteria per cubic foot for both types of rooms. A normal probability plot and boxplot
indicate that the data are approximately normally distributed with no outliers. Do carpeted rooms have more bacteria than uncarpeted rooms at the a 0.05 level of significance?
Full data set O
Carpeted
8.1
13.1
6.1
Uncarpeted
14.4 9.5
14.
13
13.8 11.7 7
13
10.2
9.4
8.7
8.9
E Click the icon to view the Student t-distribution table.
What are the null and altemative hypotheses?-
Ho: carpet < Hno carpet versus H1
Hno carpet
Calculate the test statistic, to
to = (Round to two decimal places as needed.)
Now find the critical value. Select the correct choice below and fill in the answer box within your choice.
(Round to three decimal places as needed.)
OA l=
OB. tu/2=
Do carpeted rooms have more bacteria than uncarpeted rooms at the a=0.05 level of significance?
O A. No, because the test statistic is in the critical region.
O B. Yes, because the test statistic is in the critical region.
O C. Yes, because the test statistic is not in the critical region.
O D. No, because the test statistic is not in the critical region.
Expert Solution
Step 1
| Carpeted | Uncarpeted |
| 8.1,13.8,11.7,13.1,13,9,6.1,8.7 | 7,14.4,9.5,10.2,14.1,9.4,13,8.9 |
The data are approximately normally distributed with no outliers.
level of significance α = 0.05
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Solved in 4 steps
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