A researcher reports that the average IQ level of students in Alaminos City National High School (ACNHS) is 110. A sample of 20 students has a mean IQ level of 106 with a standard deviation of 9. At 5% level of significance, test the claim that the IQ level of students in ACNHS is 110.
A researcher reports that the average IQ level of students in Alaminos City National High School (ACNHS) is 110. A sample of 20 students has a mean IQ level of 106 with a standard deviation of 9. At 5% level of significance, test the claim that the IQ level of students in ACNHS is 110.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A researcher reports that the average IQ level of students in Alaminos City
National High School (ACNHS) is 110. A sample of 20 students has a mean IQ
level of 106 with a standard deviation of 9. At 5% level of significance, test the
claim that the IQ level of students in ACNHS is 110.
![Solution:
Given:
x =
μ = 110
S =
α =
Step 1:
Ho: μ = 110
Ha: μ ‡ 110
Step 2: Determine the test statistic, then compute its value. Since n < 30, we will
use
x-μ
t =
9
√20
9
2.25
t =
Step 3:
From the t-value table at 0.05 level of significance, the critical value is
||
df =
| 15
n =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7e1808d-02d3-4319-b6ec-cc9e125efb7c%2Fc0fd2684-0dd6-4e90-86be-5b2a36b05703%2Fx9ea64c_processed.png&w=3840&q=75)
Transcribed Image Text:Solution:
Given:
x =
μ = 110
S =
α =
Step 1:
Ho: μ = 110
Ha: μ ‡ 110
Step 2: Determine the test statistic, then compute its value. Since n < 30, we will
use
x-μ
t =
9
√20
9
2.25
t =
Step 3:
From the t-value table at 0.05 level of significance, the critical value is
||
df =
| 15
n =
![Acceptance Region
or Non-Rejection
Region
-2.093
2.093
Step 4: Draw a conclusion.
Since it is a left-tailed test and the t-computed value is
than the critical value of
we
therefore conclude that
25
Rejection Region
which is
the null hypothesis. We](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7e1808d-02d3-4319-b6ec-cc9e125efb7c%2Fc0fd2684-0dd6-4e90-86be-5b2a36b05703%2Fnepw3cj_processed.png&w=3840&q=75)
Transcribed Image Text:Acceptance Region
or Non-Rejection
Region
-2.093
2.093
Step 4: Draw a conclusion.
Since it is a left-tailed test and the t-computed value is
than the critical value of
we
therefore conclude that
25
Rejection Region
which is
the null hypothesis. We
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