A researcher plans to conduct an experiment evaluating the effect of a treatment. A sample of n = 9 participants is selected, and each person receives the treatment before being tested on a standardized dexterity task. The treatment is expected to lower scores on the test by an average of 30 points. For the regular population, scores on the dexterity task form a normal distribution with µ = 240 and σ = 30. Use the Distributions tool to answer the questions that follow.   If the researcher uses a two-tailed test with α = .05, what is the power of the hypothesis test? The power for the test is the probability of obtaining a z-score    than   , which is p =   .   Again, assuming a two-tailed test with α = .05, what is the power of the hypothesis test if the sample size is increased to n = 25? The power for the test is the probability of obtaining a z-score    than   , which is p =

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A researcher plans to conduct an experiment evaluating the effect of a treatment. A sample of n = 9 participants is selected, and each person receives the treatment before being tested on a standardized dexterity task. The treatment is expected to lower scores on the test by an average of 30 points. For the regular population, scores on the dexterity task form a normal distribution with µ = 240 and σ = 30. Use the Distributions tool to answer the questions that follow.

 

If the researcher uses a two-tailed test with α = .05, what is the power of the hypothesis test?
The power for the test is the probability of obtaining a z-score    than
 
, which is p =
 
.
 
Again, assuming a two-tailed test with α = .05, what is the power of the hypothesis test if the sample size is increased to n = 25?
The power for the test is the probability of obtaining a z-score    than
 
, which is p =
 
.
Expert Solution
Step 1

Given,

Population mean before treatment = 240

Population mean after treatment = 210

Standard deviation is 30.

σm=σn=309=10

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